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Natalija [7]
3 years ago
13

I need help with this ASAP

Mathematics
1 answer:
Law Incorporation [45]3 years ago
4 0

Answer:

12.56637061 ?????

Step-by-step explanation:

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Find thee consecutive even integers such that the sum of twice the smallest number and three times the largest is 42
tekilochka [14]

Answer:

7,8,9

Step-by-step explanation:

The closest you can get to 42 with that equation and it has to use consecutive intergers is 41 and these numbers get you there.

4 0
3 years ago
Solve the proportion.<br> u/2 = 4/1 <br><br> U=
Lelechka [254]

\dfrac{u}{2}  =  \dfrac{4}{1}

\implies \: u \:  =  \frac{4}{1}  \times 2

\implies \: u = 8

3 0
3 years ago
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How many triangles exist with the given angle measures? 55°, 45°, 90° ?
tankabanditka [31]
More than one triangle <span>exists with the given angle measures. So, this triangle is not equiangular, but has only 2 angles of equal measure.                                                                              

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4 0
3 years ago
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What is (1\4 + 7\8) - 1\3
Viefleur [7K]
19/24 is the answer to your question.
3 0
3 years ago
Read 2 more answers
Can some explain how to do this.
KatRina [158]

We can simplify the expression by using exponent properties, and we will see that the correct option is the fourth option.

<h3>How to simplify the expression?</h3>

Remember the exponent property:

\frac{a^n}{a^m} = a^{n - m}

Here we have the expression:

\frac{83.9*10^{12}*2.87*10^{-3}}{3.76*10^2}

We can reorder this to get:

\frac{83.9*10^{12}*2.87*10^{-3}}{3.76*10^2} = \frac{83.9*2.87}{3.76}*\frac{10^{12}*10^{-3}}{10^2}

The right side can be simplified to:

\frac{83.9*2.87}{3.76}*\frac{10^{12}*10^{-3}}{10^2} = 64.04*10{12 - 3 - 2} = 64.04*10^{7}

Now, we can move the decimal point one time to the left and increase the exponent by one, so we get:

6.404*10^8

Then we conclude that the correct option is the last one (where I rounded the expression to only 3 values after the decimal point).

If you want to learn more about scientific notation:

brainly.com/question/5756316

#SPJ1

3 0
2 years ago
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