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Ghella [55]
3 years ago
5

Define Triple point of water?​

Chemistry
2 answers:
Ilia_Sergeevich [38]3 years ago
6 0
<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2>_____________________________________</h2><h2>TRIPLE POINT:</h2>

Triple point is that temperature, at which the substance is found in all three states i.e. solid, liquid and gas. Every substance has different triple point, because Triple point is just above the freezing point and each substance has different freezing and boiling point.

<h2>_____________________________________</h2><h2>WATER:</h2>

Water has a Melting point or Freezing Point (MP or FP) of 0^0 C or 273K and Boiling point (BP) 100^{0} C or 373 K. Since the triple point is just above the MP or FP thus Triple Point of water is 0.01^{0}C or 273.16K.

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2><h2 />
tigry1 [53]3 years ago
6 0

Answer:

0.01 degrees centigerade

Explanation:

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Gaseous methane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water. If 2.59 g of water is produc
max2010maxim [7]

<u>Answer:</u> The percent yield of the water is 31.98 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For methane:</u>

Given mass of methane = 6.58 g

Molar mass of methane = 16 g/mol

Putting values in equation 1, we get:

\text{Moles of methane}=\frac{6.58g}{16g/mol}=0.411mol

  • <u>For oxygen gas:</u>

Given mass of oxygen gas = 14.4 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of oxygen gas}=\frac{14.4g}{32g/mol}=0.45mol

The chemical equation for the combustion of methane is:

CH_4+2O_2\rightarrow CO_2+2H_2O

By Stoichiometry of the reaction:

2 moles of oxygen gas reacts with 1 mole of methane

So, 0.45 moles of oxygen gas will react with = \frac{1}{2}\times 0.45=0.225mol of methane

As, given amount of methane is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction

2 moles of oxygen gas produces 2 moles of water

So, 0.45 moles of oxygen gas will produce = \frac{2}{2}\times 0.45=0.45 moles of water

  • Now, calculating the mass of water from equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 0.45 moles

Putting values in equation 1, we get:

0.45mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(0.45mol\times 18g/mol)=8.1g

  • To calculate the percentage yield of water, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of water = 2.59 g

Theoretical yield of water = 8.1 g

Putting values in above equation, we get:

\%\text{ yield of water}=\frac{2.59g}{8.1g}\times 100\\\\\% \text{yield of water}=31.98\%

Hence, the percent yield of the water is 31.98 %

4 0
3 years ago
An objective that revolves around a planet is...<br><br> A) star<br> B) moon<br> C)dwarf planet
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Answer:

B. Moon

Explanation:

An object revolving around a star is a planet or a dwarf planet (dependent on size).

An object revolving around a planet is a moon.

An object revolving around a black hole is a goner.

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