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Ghella [55]
3 years ago
5

Define Triple point of water?​

Chemistry
2 answers:
Ilia_Sergeevich [38]3 years ago
6 0
<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2>_____________________________________</h2><h2>TRIPLE POINT:</h2>

Triple point is that temperature, at which the substance is found in all three states i.e. solid, liquid and gas. Every substance has different triple point, because Triple point is just above the freezing point and each substance has different freezing and boiling point.

<h2>_____________________________________</h2><h2>WATER:</h2>

Water has a Melting point or Freezing Point (MP or FP) of 0^0 C or 273K and Boiling point (BP) 100^{0} C or 373 K. Since the triple point is just above the MP or FP thus Triple Point of water is 0.01^{0}C or 273.16K.

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2><h2 />
tigry1 [53]3 years ago
6 0

Answer:

0.01 degrees centigerade

Explanation:

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4 years ago
Calculate normality and tire of KOH solution , if CN H2 C2 O4 solution , that is nessesary for titration is 0.1050 mol/1 and the
kozerog [31]

Answer:

Normality of KOH = 0.1062 N

<em>Note: The given question is not clearly stated. A related question below is answered and explained;</em>

<em> What is the NORMALITY of a solution of KOH if 45.18 mL are required to neutralize 0.3g of pure oxalic acid H2C2O4 . 2H2O?</em>

Explanation:

Equation of the reaction: 2KOH + H₂C₂O₄.2H₂O --> K₂C₂O₄ + 4H₂O

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From the equation of reaction, 2 moles of KOH are required to neutralize 1 mole of H₂C₂O₄.2H₂O

Number of moles of KOH required to neutralize 0.0024 moles of H₂C₂O₄.2H₂O = 2 * 0.0024 = 0.0048 moles

Molar concentration of 45.18 mL solution of KOH containing 0.0048 moles of  KOH = number of moles/volume (L)

molarity of KOH solution = (0.0048/45.18 mL) * (1000 mL/1 L) = 0.1062 mol/L

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where is the number of moles of OH⁻ ions produces from  mole of KOH = 1

Normality of KOH = 1 * 0.1062

Normality of KOH = 0.1062 N

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