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sineoko [7]
3 years ago
14

Gas A effuses 0.68 times as fast as Gas B. If the molar mass of Gas B is 17 g, what is the mass of Gas A?

Chemistry
1 answer:
BartSMP [9]3 years ago
4 0
The mass of gas A is 11.56. i got this answer by 0.68 multiplied by 17.  because in this problem the key word is times.
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need help is due tommorow about glacier.the question is this how might this affect the earth contients?
mestny [16]
Well the glaciers can melt and add more water to the oceans/seas and some animals that live in the North Pole will have no where to go...EXAMPLE: polar bears ,penguins, walruses, etc use the glaciers. Polar bears jump onto them to get to land or if they are fighting a walrus they have more fighting ground on land than in the water,etc. (There's a lot more info I just don't know if it's the correct info but what I'm telling you right now is 90% true lol.) also some of the land land can sink like islands or peninsulas(I think)
3 0
3 years ago
At 298 K, the osmotic pressure of a glucose solution (C6H12O6 (aq)) is 12.1 atm. Calculate the freezing point of the solution. T
Anarel [89]

<u>Answer:</u> The freezing point of solution is -0.974°C

<u>Explanation:</u>

  • To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

where,

\pi = osmotic pressure of the solution = 12.1 atm

i = Van't hoff factor = 1 (for non-electrolytes)

M = molarity of solute = ?

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature of the solution = 298 K

Putting values in above equation, we get:

12.1atm=1\times M\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\M=\frac{12.1}{1\times 0.0821\times 298}=0.495M

This means that 0.495 moles of glucose is present in 1 L or 1000 mL of solution

  • To calculate the mass of solution, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of solution = 1.034 g/mL

Volume of solution = 1000 mL

Putting values in above equation, we get:

1.034g/mL=\frac{\text{Mass of solution}}{1000mL}\\\\\text{Mass of solution}=(1.034g/mL\times 1000mL)=1034g

  • To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of glucose = 0.495 moles

Molar mass of glucose = 180.16 g/mol

Putting values in above equation, we get:

0.495mol=\frac{\text{Mass of glucose}}{180.16g/mol}\\\\\text{Mass of glucose}=(0.495mol\times 180.16g/mol)=89.18g

Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

  • The equation used to calculate depression in freezing point follows:

\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Freezing point of pure solution = 0°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_f = molal freezing point elevation constant = 1.86°C/m

m_{solute} = Given mass of solute (glucose) = 89.18 g

M_{solute} = Molar mass of solute (glucose) = 180.16  g/mol

W_{solvent} = Mass of solvent (water) = [1034 - 89.18] g = 944.82 g

Putting values in above equation, we get:

0-\text{Freezing point of solution}=1\times 1.86^oC/m\times \frac{89.18\times 1000}{180.16g/mol\times 944.82}\\\\\text{Freezing point of solution}=-0.974^oC

Hence, the freezing point of solution is -0.974°C

8 0
3 years ago
What is boiling point​
frutty [35]

Answer:

Its the temperature at which the molecules of a matter especially a liquid attain higher kinetic energy and the rate of collision becomes increased

Explanation:

8 0
3 years ago
What is the difference between atomic mass, relative atomic mass and average atomic mass
vesna_86 [32]

\bold{\huge{\underline{\purple{ Answer }}}}

<u>Difference </u><u>between </u><u>Atomic </u><u>mass</u><u>, </u><u>relative </u><u>atomic </u><u>mass </u><u>and </u><u>average </u><u>atomic </u><u>mass</u><u> </u><u>:</u><u>-</u>

<h3><u>Atomic </u><u>Mass </u><u>:</u><u>-</u></h3>

  • Atomic mass is the mass of neutrons and protons present in the nucleus of an atom .
  • It is always calculated for a single element and having direct value
  • For isotopes also, the atomic mass is calculated separately . Example :- <u>Carbon </u><u>1</u><u>2</u><u> </u><u>,</u><u> </u><u>carbon </u><u>1</u><u>3</u><u> </u><u>and </u><u>carbon </u><u>1</u><u>4</u><u> </u><u>have </u><u>different </u><u>atomic </u><u>mass</u><u>. </u>
  • The SI unit of Atomic mass is " u" and "amu"

<h3><u>Relative </u><u>Atomic </u><u>mass </u><u>:</u><u>-</u></h3>

  • Relative atomic mass is mean mass of the atoms of an element which is compared to the 1/12th mass of carbon - 12 .
  • Carbon - 12 is taken as a relative when we calculate the relative atomic mass of any element
  • For calculating relative atomic mass, we need to know the masses, percentage and abundance of all types of elements
  • Relative atomic mass is a dimension less quantity

<h3><u>Average </u><u>Atomic </u><u>Mass </u><u>:</u><u>-</u></h3>

  • Average atomic mass is the average mass of an atoms of a particular element by considering it's isotopes
  • While we calculate average atomic mass is a standardized number. Whereas, Average atomic mass sometimes varies geologically .
  • It also includes percentage, abundance and masses of given element .
  • In average atomic mass, We do not compare mean value with the 1/12 mass of carbon - 12
  • The unit of Average atomic mass is "Amu" or " u " .
5 0
2 years ago
15. An electrically neutral atom consists of 15 neutrons, 13 electrons, and a number of protons. What is its mass number?​
Korvikt [17]

Answer:

28

Explanation:

it states that the atom is neutral, meaning the number of electrons and protons are the same. so if there are 13 electrons, there are 13 protons. And the mass number is neutrons plus protons. So 13+15 is 28

4 0
3 years ago
Read 2 more answers
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