The volume of water displace by crown is 10.7 mL. This will be equal to the volume of crown. Mass of crown is 112 g.
Density of a substance is defined as mass of substance per unit volume. It is mathematically represented as follows:

Putting the values,

The theoretical value of density of silver is
also, 1 mL is equal to
thus, density will be 10.5 g/mL.
This is approximately equal to the calculated value thus, the crown is made up of silver.
<span><span>When the solvent disrupts the solvents ability to form that crystal lattice and thus need lower temperatures (freezing point depression) than normally expected to form the solid. </span>
My guess would be: B. The solute disrupts crystals formation by the solvent
</span>
Answer:
Ethyl acetate is a polar solvent.
Explanation:
As you can see, the image below shows the chemical formula of Ethyl acetate. This compound has two oxygen atoms, whose electronegativity is greater than that of the carbon atom to which they are attached, the dipole moment of this molecule is nonzero. This phenomenon causes this compound to form dipole-dipole bonds with other polar molecules. This also means that polar compounds can dissolve in Ethyl acetate.
Sodium chloride is made up of sodium and chlorine.
sodium chlorine would form an ionic bond, which is the transfer of electrons
because sodium is in group 1, it has 1 electron on its outermost shell
because chlorine is in group 7, it has 7 electrons on the outermost shell.
sodium and chlorine both want a full outer shell. therefore, sodium and chlorine will form an ionic bond, and sodium will transfer its one electron to chlorine so that it can lose its electron and get a full outer shell, and chlorine can gain an electron and also get a full outer shell. this can be represented using the dot and cross model. as shown in the picture.
but don't forget to add a 1- charge to chlorine with brackets and a 1+ charge to sodium, also with brackets.
hope this helped.. I know it became really long but I didn't really realise it once I was half way.. anyway, if you have any questions just ask :)