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sineoko [7]
3 years ago
14

Gas A effuses 0.68 times as fast as Gas B. If the molar mass of Gas B is 17 g, what is the mass of Gas A?

Chemistry
1 answer:
BartSMP [9]3 years ago
4 0
The mass of gas A is 11.56. i got this answer by 0.68 multiplied by 17.  because in this problem the key word is times.
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What volume will be occupied by 5.00 mol of a gas at 25°C and 0.500<br> atm pressure?"
fomenos

Answer:

The volume will be occupied is 244, 36L.

Explanation:

We convert the unit of temperature to celsius into Kelvin, then use the ideal gas formula, solve for V (volume) and use the gas constant R =0.082 l atm / K mol:

0°C=273K  25°C= 273 + 25=298K

PV=nRT ---> V=nRT/P

V= 5,00 mol x 0,082 l atm/ K mol x 298 K/0,500 atm

<em>V=244,36L</em>

4 0
3 years ago
What is an isotope? atoms of the same element with different number of​
geniusboy [140]

Answer:

The same element that contain equal number if protons but different number of neurons in their nuclei and hence differ in relative atomic mass

7 0
3 years ago
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Indicate whether each of the following statements is correct or incorrect.1)Every Bronsted-Lowry acid is also a Lewis acid2)Ever
Hunter-Best [27]

Answer:

1) correct

2) incorrect

3) correct

4)incorrect

Explanation:

1) A Lewis acid is a substance that accepts a nonbonding pair of electrons.

A Bronsted-Lowry acid is a substance that donates a proton H⁺

Since the donation of a proton involves the acceptance of a pair of electrons, every Bronsted-Lowry acid is also a Lewis acid.

2)A Lewis acid not necessarily needs to have a proton to be donated.

3) Conjugated acids of weak bases are strong acids and conjugated acids of strong bases are weak acids.

4)K⁺ comes from a strong base, therefore is does not have an acidic behaviour.

4 0
3 years ago
If you are supposed to put in 2/4 a cup sugar for a recipe, can you just put in a half cup of sugar?
natta225 [31]
I would assume so.

Given \frac{2}{4}, we can simplify the fraction to \frac{1}{2}

Both would obtain the same proportions, so I don't see why putting a half cup of sugar would make things any different.

Hope this is the answer you are looking for.
8 0
3 years ago
Read 2 more answers
A volume of 125 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If
VMariaS [17]

Answer:

41.9 g

Explanation:

We can calculate the heat released by the water and the heat absorbed by the steel rod using the following expression.

Q = c × m × ΔT

where,

c: specific heat capacity

m: mass

ΔT: change in temperature

If we consider the density of water is 1.00 g/mol, the mass of water is 125 g.

According to the law of conservation of energy, the sum of the heat released by the water (Qw) and the heat absorbed by the steel (Qs) is zero.

Qw + Qs = 0

Qw = -Qs

cw × mw × ΔTw = -cs × ms × ΔTs

(4.18 J/g.°C) × 125 g × (21.30°C-22.00°C) = -(0.452J/g.°C) × ms × (21.30°C-2.00°C)

ms = 41.9 g

3 0
3 years ago
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