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3 years ago

Compounds can not be separated by Response area means. Separating a compound requires a Response areareaction.

Chemistry

1 answer:

Aleks04 [339]3 years ago

7 0

Answer:

use vinager

Explanation:

I did this heh :/

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What is the atomic mass of<br> an atom?

Alborosie

Answer:

1 unit

Explanation:

It is expressed as a multiple of one-twelfth the mass of the carbon-12 atom, 1.992646547 × 10−23 gram, which is assigned an atomic mass of 12 units.

1/12 * 12 = 1. I think so.

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2 years ago

Distinguish between kinetic energy<br> and poteintial energy-

topjm [15]

Answer:

kinetic energy is energy possessed due to its motion while potential energy is energy possessed by a body by virtue of its position relative to others

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2 years ago

The percent composition by mass of magnesium MgBr2 (gram formula mass= 184 grams/mole) is equal to...

k0ka [10]

The percent composition by mass of an element is determined by dividing the molar mass of the element by the molar mass of the compound. In this case, the molar mass of magnesium is 24. Hence the answer to this problem is A. 24/184 x 100

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3 years ago

Read 2 more answers

You are given a solution that is 518 mM lactose. You need to make up 4.5 L of 16.7 mM solution. What volume do you need to trans

OLga [1]

Answer:

The volume you need to transfer from the stock solution is 0.145 l

Explanation:

Since the number of moles of lactose in the volume of stock solution that you transfer will be the same as the number of moles of lactose in the final solution, you can use this expression:

number of moles in volume to transfer = number of moles in the final solution

Since number of moles = concentration * volume (if the concentration is expressed in molarity), then:

Ci * Vi = Cf * Vf

where:

Ci = concentration of the stock solution.

Vi = volume of the stock solution to be transferred.

Cf = concentration of the final solution

Vf = volume of the final solution

Then, replacing with the data:

518 mM * Vi = 16.7 mM * 4.5 l

Vi = 16.7 mM * 4.5 l / 518 mM

Notice that any concentration unit can be used, as long as the units of the concentration of the stock and final solution are the same.

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3 years ago

What are the two different ions present in the compound al(no3)3?

Aleks [24]

$Al^{3+}$ and $NO_3^{-}$

Aluminum nitrate is an ionic compound, meaning that it is made up cations and anions. By convention when writing the formula for an ionic compounds the cation part shall be placed in front the anions. Thus the cation would contain aluminum and the anion shall be a polyatomic nitrate ion consisting of nitrogen and oxygen. The bracket with subscript 3 attached resembles the ratio between the two species, aluminum ions and nitrate ions. For each aluminum ion in the compound there shall be three corresponding nitrate ions.

Aluminum form ions of charge +3 whereas nitrate ions are of charge -1. Write the charge of the ion as the superscript in reverse (i.e., write $3+$ as in $Al^{3+}$ and $-$ in $NO_3^{-}$ , omitting any 1.)

5 0

3 years ago