3 years ago

Compounds can not be separated by Response area means. Separating a compound requires a Response areareaction.

Chemistry

1 answer:

Aleks04 [339]3 years ago

7 0

Answer:

use vinager

Explanation:

I did this heh :/

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Silicon has 2 isotopes, Silicon-28 with an abundance of 90% and Silicon-30 with an abundance of 10%. Find the AAM for Silicon.

JulsSmile [24]

Answer:

RAM

$RAM = (mass \: of \: ^{28} Si \: \times \%abundance) + (mass \: of \: ^{30} Si \: \times \%abundance) \\ RAM = (28 \times 90\%) + (30 \times 10\%) \\ RAM = 25.2 + 3 \\ RAM = 28.2$

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3 years ago

How many moles is 3.52 x 10²⁴ molecules of water?

sveta [45]

Answer:

5.85 moles H2O

Explanation:

(3.52 x 10^24 molecules H2O) / (1) x (1 mole) / (6.02 x 10^23 molecules) = 5.85 moles H2O

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3 years ago

What are deltaTb and deltaTf for an aqueous solution that is 1.5g nacl in 0.250kg h2o? Given Kb=0.51 C/m and kr=1.86 C/m

bulgar [2K]

Answer:

$T_f$ for given question is 2.79 and $T_b$ is 0.52

$\Delta T_b = I \times K_b \times m$ {i- vant hoff’s constant ; Kb- constant ; m molarity }

M = no. of moles of the solute present in one kg of solution

Let the weight of amount of solute be “w” and its molecular mass be “M”

Let the mass of the solvent in the given question be “x”

$\Delta T_b = I \times K_b \times (w/M)/ x$

$\Delta T_b = I \times K_b \times w/Mx$

$\Delta T_b = 1 \times 0.51 \times1.5/(0.250 \times 58.44) = 0.052$

$\Delta T_f = M \times K_f = 1.86 \times 1.5 = 2.79$

4 0

3 years ago

Calculate the ph of the solution 0.2M Mg(OH)2

Kipish [7]

Mg(OH)2 is base

Oh = 0.2 x 2 = .4

Poh = - Log (.4)

= .3979

Ph + Poh = 14

Ph = 14 - .3979

= 13.60

6 0

3 years ago

Read 2 more answers

If this is a p1000 micropipette, then this is set to dispense [ Select]ul. If this is a p10

mariarad [96]

Answer:

1000 µL; 10 µL

Explanation:

A p1000 micropipet is set to dispense 1000 µL.

A p10 micropipet set to dispense 10 µL.

3 0

4 years ago