Answer:
Explanation:
Assumptions is that
1. The flow is an unsteady one
2. Bubbles diameter is constant
3. The bubble velocity is slow
4. There is no homogenous reaction
5. It has a one dimensional flux model along the radial direction
A series of end-milling cuts is currently used to produce an aluminum part that is an aircraft component. The purpose of the mac
1 answer:
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ANSWERS:
Explanation:
Given:
Piston cylinder assembly which mean that the process is constant pressure process P=C.
<u>AMMONIA </u>
state(1)
saturated vapor
The temperature
Isothermal process
a)
( double)
b)
(reduced by half)
To find the final state by giving the quality in lbf/in we assume the friction is neglected and the system is in equilibrium.
state(1)
using PVT data for saturated ammonia
then the state exists in the supper heated region.
a) from standard data
assume linear interpolation
b)
from standard data
then the state exist in the wet zone
Answer:
a.)
US Sieve no. % finer (C₅ )
4 100
10 95.61
20 82.98
40 61.50
60 42.08
100 20.19
200 6.3
Pan 0
b.) D10 = 0.12, D30 = 0.22, and D60 = 0.4
c.) Cu = 3.33
d.) Cc = 1
Explanation:
As given ,
US Sieve no. Mass of soil retained (C₂ )
4 0
10 18.5
20 53.2
40 90.5
60 81.8
100 92.2
200 58.5
Pan 26.5
Now,
Total weight of the soil = w = 0 + 18.5 + 53.2 + 90.5 + 81.8 + 92.2 + 58.5 + 26.5 = 421.2 g
⇒ w = 421.2 g
As we know that ,
% Retained = C₃ = C₂×
∴ we get
US Sieve no. % retained (C₃ ) Cummulative % retained (C₄)
4 0 0
10 4.39 4.39
20 12.63 17.02
40 21.48 38.50
60 19.42 57.92
100 21.89 79.81
200 13.89 93.70
Pan 6.30 100
Now,
% finer = C₅ = 100 - C₄
∴ we get
US Sieve no. Cummulative % retained (C₄) % finer (C₅ )
4 0 100
10 4.39 95.61
20 17.02 82.98
40 38.50 61.50
60 57.92 42.08
100 79.81 20.19
200 93.70 6.3
Pan 100 0
The grain-size distribution is :
b.)
From the diagram , we can see that
D10 = 0.12
D30 = 0.22
D60 = 0.12
c.)
Uniformity Coefficient = Cu =
⇒ Cu =
d.)
Coefficient of Graduation = Cc =
⇒ Cc = = 1
