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Yanka [14]
3 years ago
12

What was the main drawback of Ford’s assembly line?

Engineering
2 answers:
nikklg [1K]3 years ago
7 0

Answer:

b

Explanation:

eimsori [14]3 years ago
3 0

Answer: B

Explanation:

Disadvantages of assembly line production are based on the worker's point of view. Because little training is generally required, wages may not be very competitive and required many hours of labor

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can someone please define these three vocabulary words for my stem class i will give brainliest if i can figure out how
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Just use g-00gle lol
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10. True or False: You should select your mechanic before you experience vehicle failure.
ra1l [238]

Answer:

True

Explanation:

Always see a professional if you have any issues that is not in your scope of practice

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3 years ago
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Draw the six principal views of
stepan [7]

Explanation:

See what Challenge I completed on Ablo https://ablo.live/s/1/yIwE1xnX88zg0liSeC7njA

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3 years ago
The Ethernet (CSMA/CD) alternates between contention intervals and successful transmissions. Assume a 100 Mbps Ethernet over 1 k
Vesnalui [34]
<h3><u>CSMA/CD Protocol: </u></h3>

Carrier sensing can transmit the data at anytime only the condition is before sending the data sense carrier if the carrier is free then send the data.

But the problem is the standing at one end of channel, we can’t send the entire carrier. Because of this 2 stations can transmit the data (use the channel) at the same time resulting in collisions.

There are no acknowledgement to detect collisions, It's stations responsibility to detect whether its data is falling into collisions or not.

<u>Example: </u>

T_{P}=1 H r, at time t = 10.00 AM, A starts, 10:59:59 AM B starts at time 11:00 AM collision starts.

12:00 AM A will see collisions

Pocket Size to detect the collision.

\begin{aligned}&T_{t} \geq 2 T_{P}\\&\frac{L}{B} \geq 2 T_{P}\\&L \geq 2 \times T_{P} \times B\end{aligned}

CSMA/CD is widely used in Ethernet.

<u>Efficiency of CSMA/CD:</u>

  • In the previous example we have seen that in worst case 2 T_{P} time require to detect a collision.
  • There could be many collisions may happen before a successful completion of transmission of a packet.

We are given number of collisions (contentions slots)=4.

\text { Propagation day }=\frac{\text {distance}}{\text {speed}}

Distance = 1km = 1000m

\begin{aligned}&\text { Speed }=2 \times 10^{8} \mathrm{m} / \mathrm{sec}\\ &T_{P}=\frac{1000}{2 \times 10^{8}}=(0.5) \times 10^{-5}=5 \times 10^{-6}\\ &T_{t}=5 \mu \mathrm{sec}\end{aligned}

7 0
3 years ago
If a hoist lifts a 4500lb load 30ft in 15s, the power delivered to the load is a) 18.00hp b) 9000hp c) 16.36hp d) None of the ab
12345 [234]

Answer:

Explanation:

load = 4500lb                   lift height= 30 ft

time =15 s

velocity=\frac{30}{15} ft/s

velocity=2 ft/s

power = force\times velocity

power={4500}\times2

power= 9000 lb ft/s

1 hp= 550 lb ft/s

power= \frac{9000}{550} =16.36 hp

5 0
3 years ago
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