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san4es73 [151]
3 years ago
15

Answer the following questions about your own experience in the labor force.

Engineering
1 answer:
liubo4ka [24]3 years ago
4 0

Answer:

Following are the solution to this question:

Explanation:

In point a:

This takes me six weeks for both the took ideas that I was searching for but it continued for 3 years (12 weeks) as it's an intern.  

In point b:

Finding job:

\to f =  \frac{1}{6} = 0.166 jobs weekly  

Separation of jobs:

\to \frac{ 1}{12}=0.083 employment per week.  

In point c:

Its natural rate of unemployment is:  \frac{U}{L} = s+(s \times f).  

The normal level of employment for that community I represent, once we add up from that preceding section, is as follows:

\to \frac{U}{L} = 0.083+ (0.083\times 0.166) = 0.096

If on average, it requires six weeks to find another job or the work lasted 12 weeks, the group's unemployment level is 0.096 \ \%.

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The beam below will be subjected to a live load of 600 lb/ft, a concentrated live load of 25 kip, and a dead load of 300 lb/ft.
snow_tiger [21]

Answer:

hello some part of your question is missing below is the complete question

answer :

A) 162750 Ib.ft

B) - 64950 Ib.ft

Explanation:

Applying Muller-Breslau's law

we will make assumptions which include assuming an imaginary hinge at G

therefore the height of I.LD for B.M at G = ( 12 * 8 ) / 20 = 4.8

height of I.L.D at C = 2.4 ( calculated )

height of I.L.D at F = 1.5 ( calculated )

A) Determine Maximum positive moment produced at G

M ^+ = [ (1/2 * 20 * 4.8 ) ( 600 + 300 ) ] + [ ( 25 * 4.8 * 10^3 ) ] - [ ( 1/2 *2.4*20 ) * 300 ] + [ (1/2 * 1.5 * 10 ) ( 600 + 300 ) ]

      = 162750 Ib.ft

B)   Determine the maximum negative moment produced at G

M ^- = [ ( 1/2 * 20 * 4.8 ) * 300 ] - [ ( 1/2 * 2.4 * 20 ) ( 600 + 300 ) ] - [ (2.5 * 10^3 * 2.4 ) ] + [ ( 1/2 * 1.5 * 10) * 300 ]

     = - 64950 Ib.ft

4 0
3 years ago
A seamless pipe 800mm diameter contains a fluid under a pressure of 2N/mm2. If the permissible tensile stress is 100N/mm2, find
Bad White [126]

Answer:

8 mm

Explanation:

Given:

Diameter, D = 800 mm

Pressure, P = 2 N/mm²

Permissible tensile stress, σ = 100 N/mm²

Now,

for the pipes, we have the relation as:

\sigma=\frac{\textup{PD}}{\textup{2t}}

where, t is the thickness

on substituting the respective values, we get

100=\frac{\textup{2\times800}}{\textup{2t}}

or

t = 8 mm

Hence, the minimum thickness of pipe is 8 mm

3 0
3 years ago
In Lab 7, we worked through a program that displayed the homeless shelter occupancy over time. The same approach can be used for
Bezzdna [24]

Answer:

Explanation:

The python code to generate this is quite simple to run.

i hope you understand everything written here, you can as well try out other problems to understand better.

First to begin, we import the package;

Code:

import pandas as pd

import matplotlib.pyplot as plt

name = input('Enter name of the file: ')

op = input('Enter name of output file: ')

df = pd.read_csv(name)

df['Date'] = pd.to_datetime(df["Date"].apply(str))

plt.plot(df['Date'],df['Absent']/(df['Present']+df['Absent']+df['Released']),label="% Absent")

plt.legend(loc="upper right")

plt.xticks(rotation=20)

plt.savefig(op)

plt.show()

This should generate the data(plot) as seen in the uploaded screenshot.

thanks i hope this helps!!!

6 0
3 years ago
Which of these credit building options do you personally think is the easiest method that you can see yourself doing? Explain yo
enot [183]

Answer:

Explanation:

Your 3-B Annual Credit Reports & Scores with Enhanced Credit Report Monitoring.

Trusted by Millions

7 0
3 years ago
A laboratory in the Y building keep a vacuum pressure of 0.1 kPa abs. What is the net force acting on the door considering the a
seropon [69]

Answer:

net force acting on the floor is 100 kN

Explanation:

Given data:

P_{vaccum} = 0.1 kPa

P_{atm} = 101.325 kPa

dimension of floor = 2 m \times 0.5 m

we know that

Net force can be calculated as follow

f_{net} = P_{vaccum} \times area

f_{net} = 0.1\times 10^3 \times 2\times 0.5

f_{net} = 0.1\times 10^3 \times 1

f_{net} = 100 kN

Therefore net force acting on the floor is 100 kN

7 0
4 years ago
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