How do particles of salt and dust affect cloud formation?
1 answer:
You might be interested in
The Balanced chemical equation of reaction of Borane with oxygen is as follow,
B₂H₆ + 3O₂ -----> 2HBO₂ + 2H₂O
According to this equation 27.66 g (1 mole) of B₂H₆ reacts with oxygen to produce 36 g (2 moles) of water.
The amount of water produced when 19.2 g of B₂H₆ reacted is calculated as follow,
= 
Solving for x,
x = (36 g of H₂O ₓ 19.2 g of H₂B₆) / 27.66 g of B₂H₆
x = 24.98 g of H₂O
Result:
24.98 g of water is produced when 19.2 g of B₂H₆ is reacted with excess of oxygen.
B₂H₆ + 3O₂ -----> 2HBO₂ + 2H₂O
According to this equation 27.66 g (1 mole) of B₂H₆ reacts with oxygen to produce 36 g (2 moles) of water.
The amount of water produced when 19.2 g of B₂H₆ reacted is calculated as follow,
Solving for x,
x = (36 g of H₂O ₓ 19.2 g of H₂B₆) / 27.66 g of B₂H₆
x = 24.98 g of H₂O
Result:
24.98 g of water is produced when 19.2 g of B₂H₆ is reacted with excess of oxygen.
<u>Answer:</u> The mass of water that must be reacted is 56.28 grams.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
....(1)
Given mass of oxygen = 50 g
Molar mass of oxygen = 32.00 g/mol
Putting values in equation 1, we get:
For the given chemical equation:
By Stoichiometry of the reaction:
1 mole of oxygen is produced when 2 moles of water is reacted.
So, 1.5625 moles of oxygen is produced when = of water is reacted.
To calculate the mass of water, we use equation 1:
Moles of water = 3.125 moles
Molar mass of water = 18.01 g/mol
Putting values in equation 1, we get:
Hence, the mass of water that must be reacted is 56.28 grams.