Answer:
Twice as much.
Explanation:
That's because the freezing point depression depends on the total number of solute particles.
C₆H₁₂O₆(s) ⟶ C₆H₁₂O₆(aq)
0.01 mol of C₆H₁₂O₆ gives 0.01 mol of solute particles.
NaCl(s) ⟶ Na⁺(aq) + Cl⁻(aq)
1 mol of NaCl gives 0.01 mol of Na⁺(aq) and 0.01 mol of Cl⁻(aq).
That's 0.02 mol of particles, so the freezing point depression of 0.01 mol·L⁻¹ NaCl will be twice that of 0.01 mol·L⁻¹ C₆H₁₂O₆.
Answer: The answer is frequency.
Explanation: If the wavelength is long, the frequency will be low. If the wavelength is short, the frequency will be high.
i dont really know i will find some more information on that in about 5 minutes
Answer: Temperature is an example of a quantitative variable
Explanation:
A quantitative variable is defined as :
- A variable that can assume a numerical value .
- It can be ordered with respect to either magnitude or dimensions.
- It is further classified into two types : interval scale and ratio scale.
Temperature comes under interval scale , because interval scale has no zero point.
For example : A 0° C Celsius does not interpret that there is no temperature.
Therefore , Temperature is an example of a quantitative variable.
Hence, the correct answer is "quantitative variable"
Answer:
Cu(s) in Cu(NO₃)₂(aq)
Explanation:
The standard reduction potential (E°) is the energy necessary to reduce the atom in a redox reaction. When an atom reduces it gains electrons from other than oxides. As higher is E°, easily it will reduce. The substance that reduces is at the cathode of a cell, where the electrons go to, and the other that oxides are at the anode of the cell.
The standard reduction potentials from Al(s) and Cu(s) are, respectively, -1.66V and +0.15V, so the half-cell of Cu(s) in Cu(NO₃)₂(aq) is the cathode.
