Question

A 6.3 μC electric charge is placed in an Electric Field with a magnitude of 5.0 x 105 charge due to the Electric Field? N/C. What is the electric force on the charge due to the electric field

Answer 1

Answer:

F = 3.15 N

Explanation:

Given electric charge, q = 6.3 μC

The magnitude of electric field, $E=5\times 10^5\ N/C$

We need to find the electric force on the charge due to the electric field. The electric force is given by :

F = qE

Putting all the values,

$F=6.3\times 10^{-6}\times 5\times 10^5\\\\F=3.15\ N$

So, the required force on the charge is 3.15 N.