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12a + 6 + 3a = 15a + 2
15a = 15a - 4
0 = - 4
The vertices of the quadrilateral ABCD lie on the sides of quadrilateral PQRS then the sum of the degree of measures of the eight indicated angles would be 360.
Answer:
![-7, -2, 3, 11](https://tex.z-dn.net/?f=-7%2C%20-2%2C%203%2C%2011)
Step-by-step explanation:
Negative numbers are "smaller" than positive numbers. Just arrange them.
2 is not a composite number