The electric field strength is inversely related to the square of the distance.so the strength of the electric field is given by
Here, is constant depend upon medium and its value is and q is charge and r is the distance.
Given and we know the charge of proton, .
Therefore,
Answer:
Use the method on the image and solve it.
Answer:
hello your question is incomplete attached below is the missing part
answer : short period oscillations frequency = 0.063 rad / sec
phugoid oscillations natural frequency ( ) = 4.27 rad/sec
Explanation:
first we have to state the general form of the equation
=
where :
comparing the general form with the given equation
= 18.2329
hence the short period oscillation frequency ( ) = 0.063 rad/sec
phugoid oscillations natural frequency ( ) = 4.27 rad/sec
Given: Change of x is 35.4m, Velocity Final=7.10 m/s, Velocity Initial=0m/s
Find: Acceleration
Analysis:
Vf²=Vi²+2aΔx (Velocity final squared equals Velocity initial squared plus 2 times acceleration times change of x)
(7.10 m²/s)²=(0 m/s)²+2a(35.4 m)
50.41 m/s²=(70.8 m)a
a=0.712 m/s²