Nitrogen gas is more abundant and I miss her than oxygen however nicer than to be converted into different forms to be used by m
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Answer:
The standard enthalpy of formation of methanol is, -238.7 kJ/mole
Explanation:
The formation reaction of CH_3OH will be,
The intermediate balanced chemical reaction will be,
..[1]
..[2]
..[3]
Now we will reverse the reaction 3, multiply reaction 2 by 2 then adding all the equations, Using Hess's law:
We get :
..[1]
..[2]
[3]
The expression for enthalpy of formation of will be,
The standard enthalpy of formation of methanol is, -238.7 kJ/mole
Answer:
Work done in this process = 4053 J
Explanation:
Mass of the gas = 0.092 kg
Pressure is constant = 1 atm = 101325 pa
Initial temperature = 200 K
Final temperature = 200 - 85 = 115 K
Gas constant for nitrogen = 297
When pressure of a gas is constant, volume of the gas is directly proportional to its temperature.
⇒ V ∝ T
⇒ =
------------ ( 1 )
From ideal gas equation
= m R
------ (2)
⇒ 101325 × = 0.092 × 297 × 200
⇒ = 0.054
This is the volume at initial condition.
From equation 1
⇒ =
⇒ = 0.094
This is the volume at final condition.
Thus the work done is given by W = P [ -
]
⇒ W = 101325 × [ 0.094 - 0.054]
⇒ W = 4053 J
This is the work done in that process.