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kolbaska11 [484]
4 years ago
5

What is the purpose of strawberry seeds

Chemistry
1 answer:
Neporo4naja [7]4 years ago
7 0

Answer:

The goal there is for the fruit to not get eaten, so that the seed can rely on the fruit's nutrients to support its growth.” Presumably, the strawberry went for evolutionary option number one – attract something to spread the seeds  

Explanation:

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what concept from chemistry was the most challenging and why? what can you do to learn more about this concept as you progress t
qwelly [4]

The most difficult concept will be the concept of patient drug tolerance because there are many drugs that have different side effects for different patients. Therefore, it is necessary to understand the response of certain drugs to different patients. This will help avoid wrong drug combinations. This can cause side effects.

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Another topic in chemistry that is most tough to understand is moles. We can understand this concept by understanding the fact mole is an amount of a substance which may be atoms, molecules, ions, etc which have exactly 6.02214076 * 1023 'elementary entities' of the substance.

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6 0
2 years ago
How many grams in one molecule of c12h22o11?
patriot [66]
There are 342.29648  grams in 1 molecule
6 0
4 years ago
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Zanzabum

Answer:

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Explanation:

3 0
2 years ago
How many moles of Ni(OH)2 are soluble in 1L of sodium hydroxide (NaOH) when the pH is 12.34?
kakasveta [241]

Answer:

⇒ 3.312 E-13 mol Ni(OH)2 are soluble in 1 L of solution (NaOH)

Explanation:

  • Ni(OH)2 ↔ Ni2+  +  2OH-

            S              S        2S + 0.0218

∴ pKsp Ni(OH)2 = 15.8 = -Log Ksp

⇒ Ksp = 1.585 E-16 = [ Ni2+ ] * [ OH- ]²

  • NaOH ↔ Na+  +  OH-

∴ pH = 12.34

⇒ pOH = 14- 12.34 = 1.66 = - Log [ OH- ]

⇒ [ OH- ] = 0.0218 M

⇒ Ksp = 1.585 E-16 = S * ( 2S + 0.0218 )²

if we compare the concentration ( 0.0218 ) with the Ksp ( 1.585 E-16 ), then we can neglect the solubility as adding

⇒ 1.585 E-16 = S * ( 0.0218 )²

⇒ 1.585 E-16 = 4.786 E-4 * S

⇒ S  = 3.312 E-13 mol/L

∴  soluble moles Ni(OH)2 = 3.312 E-13 mol/L * 1 L Sln = 3.312 E-13 moles

⇒ % S = ( 3.312 E-13 / 0.0218 ) * 100 = 1.513 E-11 %.....we can accept the previous assumption.

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3 years ago
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