Answer:
Reducing or increasing the amount of H+ ions / hydronium (H3O+) ions
Explanation:
To reduce the pH (reducing the strength of the acid) can be done by adding a base (including a conjugate base such as bicarbonate ion) which will absorb the H+ ions either through adsorption or reaction.
Adding more H+ decreases the pH of the acid making it stronger. This can be done by adding HCL that will dissociate and increase the H+ ions.
Answer:
The answer to your question is MgSO₄ 5H₂O
Explanation:
Data
mass of MgSO₄ = 2.86 g
mass of H₂O = 2.14 g (5 - 2.86)
Process
1.- Calculate the molecular mass of the compounds
MgSO₄ = 24 + 32 + (16 x 4) = 120
H₂O = 16 + 2 = 18
2.- Convert the grams obtain to moles
120 g of MgSO₄ --------------- 1 mol
2.8 g ---------------- x
x = (2.8 x 1)/120
x = 0.024 moles
18 g of H₂O --------------------- 1 mol
2.14 g -------------------- x
x = (2.14 x 1)/18
x = 0.119
3.- Divide by the lowest number of moles
MgSO₄ = 0.024/0.024 = 1
H₂O = 0.119/ 0.024 = 5
4.- Write the molecular formula
MgSO₄5H₂O
Answer:
Aquatic ecosystem has two components -
- Biotic components
2.Abiotic components
temperature and amount of sunlight are the part of abiotic component .
while living things like sponges and planktons are the biotic components of ecosystem.
Explanation:
aquatic components are of two types-
freshwater ecosystem( lakes and ponds, river and streams)
marine ecosystem(ocean ecosysyem, estuaries)
planktons-
planktons are found in limnetic zone, availability of sunlight is much here. planktons are zooplanktons and phytoplanktons are very important link in aquatic ecosystem.
sponges
In marine water, the <em>benthic zone</em> is the area below the<em> pelagic zone.</em> Here temperature decreased because of less light perception. This zone is very nutrient rich so organisms which are present here are- bacteria, fungi, sea anemone, sponges and some fishes.
Equilibrium is reached when the net reaction is zero. The reaction is consistent, when reactants and products are neither excessively consumed, nor produced.
The rate of the forward reaction is equal to the rate of the reverse reaction.
We find the weight of the empirical formula:
12.0107 + 2 x 1.00794 + 15.9994
= 30.03
Now, we divide the molecular weight by the weight of the empirical formula to find the number of times the empirical formula repeats:
90.09 / 30.03
= 3
The formula is 3(CH₂O)
C₃H₆O₃
