The transformations are vertical translation 7 units up.horizontal translation 3 units to the left
We have given that the equations
let f(x)=x^2 and g(x)=(x-3)^2+7
We have to determine the correct transformation,
<h3>What is the vertical translation?</h3>
Vertically translating a graph is equivalent to shifting the base graph up or down in the direction of the y-axis. A graph is translated to k units vertically by moving each point on the graph k units vertically.
Notice that the addition of 2 units to the variable x in the exponent involves a horizontal shift to the left in 2 units.
Notice as well that subtraction of 4 units to the functional expression involves a vertical shift downwards in 4 units.
To learn more about the transformation visit:
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This problem can take a while if you cannot observer the answer quickly.
First of all we can see that 32=2*2*2*2*2=2^5
243, if you don't know its actually is 3^5
Now we can see that this turns into...
- 2^5/3^5
since the 5th power doesn't change the sign of the original number, we can put the negative in the ( ), if you don't know what I mean look below
(-3)^2=9 Positive
(-3)^3=-27 Negative since its to the odd power it keeps the sign.
This problem can be simplified to.
(-2/3)^5
And this is the answer :D
If you have any questions just put them in the comments.
the answer is the litter B
It will be A² + B² = C²
So 3²+5² is 34
And the square root of 34 is about 5.83
3² + 5² ≈ 5.83²
Hope that helps :)
Answer:
0.9999
Step-by-step explanation:
Let X be the random variable that measures the time that a switch will survive.
If X has an exponential distribution with an average life β=44, then the probability that a switch will survive less than n years is given by
So, the probability that a switch fails in the first year is
Now we have 100 of these switches installed in different systems, and let Y be the random variable that measures the the probability that exactly k switches will fail in the first year.
Y can be modeled with a binomial distribution where the probability of “success” (failure of a switch) equals 0.0225 and
where
equals combinations of 100 taken k at a time.
The probability that at most 15 fail during the first year is
