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2 years ago

The difference in energy on either side of the wheel is a measure of the wheel’s ___________.

Physics

1 answer:

atroni [7]2 years ago

3 0

I believe the answer is potential difference

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Two friends are walking on a hot beach on a hot summer day. one friend reports her feet are becoming hot she needs her sandals.

nata0808 [166]

Answer:

conduction

Explanation:

6 0

3 years ago

Solve 3.4 = 5.1(3.7x + 4.7) for x.

solniwko [45]

Answer:

Explanation:

3.4 = 18.87x + 23.97

collecting like terms

3.4 - 23.97 = 18.87x

-20.57 = 18.87x

dividing both sides by 18.87

x = -20.57/18.87

x= -1.09

6 0

3 years ago

Read 2 more answers

Could you pick up a nail using the curved part of the horseshoe magnet farthest from the poles?

nikitadnepr [17]

Yes

Explanation:

One can pick up a nail using the curved part of the horseshoe magnet farthest from the poles.

A horse shoe magnet has magnetic fields all around it.

In the presence of magnetic force fields, any magnetic object will be attracted to it.
This is the case with any magnet.
A magnet is any object with magnetic fields all around it.
This field causes attraction to any magnetic objects especially metals.

learn more:

Electromagnet brainly.com/question/2191993

#learnwithBrainly

5 0

3 years ago

Which best summarizes a concept related to the work-energy theorem?

Elenna [48]

Answer: When work is positive, the environment does work on an object

Explanation:

5 0

4 years ago

Robin would like to shoot an orange in a tree with his bow and arrow. The orange is hanging yf=5.00 m above the ground. On his f

kramer

Answer:

17.5 m

Explanation:

First of all, we need to find the time the arrow need to cover the horizontal distance between the starting point and the orange, which is

x = 49.0 m

We start by calculating the horizontal component of the arrow's velocity:

$v_x = v_0 cos \theta = (36.0)(cos 30.0^{\circ})=31.2 m/s$

And this horizontal velocity is constant during the entire motion. So, the time taken to reach the horizontal position of the orange is

$t=\frac{x}{v_f}=\frac{49.0}{31.2}=1.57 s$

Now we can find the height of the arrow at that time by using the equation for the vertical position:

$y=h+u_y t - \frac{1}{2}gt^2$

where:

h = 1.30 m is the initial height

$u_y = v_0 sin \theta = (36.0)(sin 30.0^{\circ})=18.0 m/s$ is the initial vertical velocity

t = 1.57 s is the time

$g=9.81 m/s^2$ is the acceleration of gravity

Substituting into the equation, we find

$y=1.30+(18)(1.57)-\frac{1}{2}(9.81)(1.57)^2=17.5 m$

6 0

3 years ago