Answer:
<em>10.90km</em>
Explanation:
Magnitude of the total displacement is expressed using the equation
d = √dx²+dy²
dx is the horizontal component of the displacement
dy is the vertical component of the displacement
dy = -6.7sin27°
dy = -6.7(0.4539)
dy = -3.042
For the horizontal component of the displacement
dx = -4.5 - 6.7cos27
dx = -4.5 -5.9697
dx = -10.4697
Get the magnitude of the bicyclist's total displacement
Recall that: d = √dx²+dy²
d = √(-3.042)²+(-10.4697)²
d = √9.2538+109.6146
d = √118.8684
<em>d = 10.90km</em>
<em>Hence the magnitude of the bicyclist's total displacement is 10.90km</em>
<em></em>
Answer:
Wouldn’t his or hers speed be 10m?
Explanation:
because 60 divided by 6 = 10
so 10m per second?
Answer:
P = 1.45 hp or 1.94kW
Explanation:
Given:
v = 2.5m/s
uk = 0.06
m = 60kg
Fk = uk*m*g*fsin(15)
Fk = 0.06*85*9.81*60*sin(15)
Fk = 776.15 N
Power=force*speed
P = F*v
P = 776.15N*2.5m/s
P = 1940.36 W
1 Horsepower = 0.7457 Kilowatts
P = 1.45 hp
Radius of circle of spiral path = 6 m
Time period = 5 s
So the total length of the path = 
time taken by bird to cover the distance = 5 s
so the speed of the bird = distance / time
so the tangential speed in horizontal direction = 7.54 m/s
vertical velocity by which it is rising upwards = 3 m/s
so the angle with the horizontal for net speed is given as
so velocity vector will make 21.7 degree with the horizontal
Answer:
Red light
Explanation:
The electromagnetic spectrum classifies all the electromagnetic waves according to their wavelength/frequency. In order from shortest to longest wavelength, we have
Gamma rays
X rays
Ultraviolet
Visible light
Infrared
Microwaves
Radio waves
All of these waves are invisible to human eye, except for the "visible light" part of the spectrum. Waves in the visible light part are perceived by human as different colors, depending on their wavelength. More specifically, they appear as follows:
Violet (380-450 nm)
Blue (450-495 nm)
Green (495-570 nm)
Yellow (570-590 nm)
Orange (590-620 nm)
Red (620-750 nm)
So we see that the longest electromagnetic wave in the visible light part of the spectrum corresponds to red light.
