We can do this with the conservation of momentum. The fact it is elastic means no KE is lost so we don't have to worry about the loss due to sound energy etc.
Firstly, let's calculate the momentum of both objects using p=mv:
Object 1:
p = 0.75 x 8.5 = 6.375 kgm/s
Object 2 (we will make this one negative as it is travelling in the opposite direction):
p = 0.65 x -(7.2) = -4.68 kgm/s
Based on this we know that the momentum is going to be in the direction of object one, and will be 6.375-4.68=1.695 kgm/s
Substituting this into p=mv again:
1.695 = (0.75+0.65) x v
Note I assume here the objects stick together, it doesn't specify - it should!
1.695 = 1.4v
v=1.695/1.4 = 1.2 m/s to the right (to 2sf)
Relatively hot objects emit visible light.
Some examples:
==> the wire coils in the toaster;
==> the spoon that you stuck in the flame on the stove;
==> the fine wire in the lightbulb when current goes through it.
VERY radioactive objects also do that. But if you're actually
standing there watching an object that's THAT radioactive,
then you're in big trouble.
(A) P(v) = 0.135v
(B) P(h) = 0.234v
<u>Explanation:</u>
Given-
Mass of the ball, m = 0.27kg
Force, F = 125N
angle of projection, θ = 30°
Let v be the velocity of the ball.
A) vertical component of the momentum of the volleyball
We know,
P(vertical) = mvsinθ
P(V) = 0.27 X v X sin 30°
P(V) = 0.27 X v X 0.5
P(V) = 0.135v
B) horizontal component of the momentum of the volleyball
We know,
P(Horizontal) = mvcosθ
P(h) = 0.27 X v X cos 30°
P(h) = 0.27 X v X 0.866
P(h) = 0.234v
Answer:
1.95m/s
Explanation:
Please view the attached file for the detailed solution.
The following were the conversion factors used in order to express all quatities in SI units:
