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UkoKoshka [18]
3 years ago
15

[H3O+] = 2.9 x 10-10 M ph level

Chemistry
1 answer:
Zinaida [17]3 years ago
5 0

Answer:

9.54

Explanation:

Fr the question given above, the following data were:

Concentration of hydronium ion [H3O⁺] = 2.9x10¯¹⁰ M

pH =?

The pH of the solution can be obtained as follow:

pH = –Log [H3O⁺]

pH = –Log 2.9x10¯¹⁰

pH = 9.54

Thus, the pH level of the solution is 9.54

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Electrolytes are substances that produce ions when they dissolve in water.

What are electrolytes?

When some substances are dissolved in water, they undergo physical or chemical changes, creating ions in solution. These substances form an important class of compounds called electrolytes. Substances that do not release ions when dissolved are called non-electrolytes. A substance is said to be a strong electrolyte if the physical or chemical process that produces ions is inherently 100% efficient (all dissolved compounds produce ions). A solute is said to be a weak electrolyte if only a relatively small portion of the solute undergoes ion production processes.

By measuring the electrical conductivity of aqueous solutions containing substances, substances can be identified as strong, weak, or non-electrolyte. To conduct electricity, a substance must contain free-moving charged species. The best known is the conduction of electricity through metal wires. In this case, the mobile charged unit is the electron.

Therefore, Electrolytes are substances that produce ions when they dissolve in water.

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2 years ago
Is carbonic acid (H2CO3) soluble in water?
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it is soluble in water

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a doctor's order is 0.125 g of ampicillin. the liquid suspension on hand contains 250 mg/5.0 ml. how many milliliters of the sus
disa [49]
0.125 g=(0.125 g)(1000 mg/1g)=125 mg.

Then, we need 125 mg of ampicillin.
5 ml of  liquid suspension contains 250 mg of ampicilling , therefore:

5 ml----------------250 mg of ampicilling
x--------------------125 mg of ampicilling

x=(5 ml * 125 mg of ampicilling) / 250 mg of ampicilling=2.5 ml

Answer: we require 2.5 ml
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4 years ago
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<u>Chemistry</u>

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<u>Step 1: Define</u>

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Given: 12 moles O₂

<u>Step 2: Stoichiometry</u>

<u />12 \ mol \ O_2(\frac{2 \ mol \ Cu}{1 \ mol \ O_2} ) = 24 mol Cu

<u>Step 3: Check</u>

<em>We are given 2 sig figs.</em>

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