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Phoenix [80]
3 years ago
7

In potassium-argon dating, how does the proportion of remaining potassium in a rock or fossil change over time?

Chemistry
2 answers:
lara [203]3 years ago
8 0

Answer:

what was the answer?

Explanation:

wariber [46]3 years ago
7 0

Answer:

it decreases

Explanation:

pennfoster

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Explanation:

Let the age to be found in years is y.

Hence,       (2480 disintegrations) \times \frac{\frac{1.0g}{0.250g}}{1.84 \times 10^{4} disintegrations}

                        = (\frac{1}{2})^{\frac{y}{5730yr}}

Solve for y as follows.

                    0.53913 = (\frac{1}{2})^{\frac{y}{5730yr}}

Now, taking log on both the sides as follows

               log 0.53913 = (\frac{z}{5730}) log \frac{1}{2}


               \frac{log 0.53913}{log (1/2)} = \frac{z}{5730}

                       z = \frac{5730 \times log 0.53913}{log (1/2)}

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