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marta [7]
3 years ago
5

The terms Q and K refer to reaction components at non-equilibrium and equilibrium conditions, respectively. For a forward reacti

on to be favored in a living cell, which of the following statements describes the relationship between Q and K?
a. The value of Q must be less than that of K.
b. The value of K must be less than that of Q.
c. No conclusion can be drawn about Q and K for a favorable process.
d. Cells are at equilibrium so none of the above statements is true
Chemistry
1 answer:
daser333 [38]3 years ago
8 0

Answer:

The value of Q must be less than that of K.

Explanation:

The difference of K and Q can be understood with the help of an example as follows

         A ⇄ B

In this reaction A is converted into B but after some A is converted , forward reaction stops At this point , let equilibrium concentration of B be [B] and let equilibrium concentration of A be [A]

In this case ratio of  [B] and  [A]  that is

K =  [B] / [A] which is called equilibrium constant.

But if we measure the concentration of A and B ,before equilibrium is reached , then the ratio of the concentration of A and B will be called Q. As reaction continues concentration of A increases and concentration of B decreases. Hence Q tends to be equal to K.

Q = [B] / [A] . It is clear that Q < K before equilibrium.

If Q < K , reaction will proceed towards equilibrium or forward reaction will

proceed .

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What volume of 0.0748 M perchloric acid can be neutralized with 115 mL of 0.244 M sodium hydroxide?
Irina18 [472]

Answer:

0.375 L

Explanation:

We know that at neutralization, the number of mol  of acid must equal the number of equivalents of base.

This is a reaction 1:1 acid to base:

HClO₄ + NaOH ⇒ NaClO₄ + H₂O

We re given the  moles  of the base indirectly since we know the volume and molarity. From there we can calculate the volume of HClO₄.

Moles NaOH = 0.115 L x 0.244 M = 0.115 L x 0.244 mol/L =0.028 mol

Thus we require 0.028 mol of HClO₄ in the pechloric acid solution:

Molarity = # moles / V ⇒ V = # moles / M

V = 0.028 mol / 0.0748 mol/L = 0.375 L

Note  that this problem can be solved in just one step since

M(HClO₄) x V(HClO₄) = M(NaOH) x V(NaOH)  ⇒

V(HClO₄) = M(NaOH) x V(NaOH) / M(HClO₄)

5 0
2 years ago
If you combine 290.0 mL 290.0 mL of water at 25.00 ∘ C 25.00 ∘C and 140.0 mL 140.0 mL of water at 95.00 ∘ C, 95.00 ∘C, what is t
Alexxandr [17]

Answer:

The final temperature is 47.79 °C

Explanation:

Step 1: Data given

Sample 1 has a volume of 290.0 mL

Temperature of sample 1 = 25.00 °C

Sample 2 has a volume of 140.00 mL

Temperature of sample 2 = 95.00 °C

Step 2: Calculate the final temperature

Heat lost = heat gained

Qlost = -Qgained

Q = m*c* ΔT

Q(sample1) = -Q(sample2)

m(sample1) * c(sample1) * ΔT(sample1) = -m(sample2)*c(sample2) *ΔT(sample2)

⇒with m(sample1) = the mass of sample 1 = 290.0 mL * 1g/mL = 290 grams

⇒with c(sample 1) = the specific heat of water = c(sample 2)

⇒with ΔT(sample 1) = the change of temperature = T2 - T1 = T2 - 25.00 °C

⇒with m(sample2) = the mass of sample 2 = 140.0 mL * 1g/mL = 140 grams

⇒with c(sample2) = the specific heat of water = c(sample1)

⇒with ΔT(sample2) = T2 -T1 = T2 - 95.00°C

m(sample1) *  ΔT(sample1) = -m(sample2)*ΔT(sample2)

290 *(T2-25.0) = -140 *(T2 - 95.0)

290 T2 - 7250 = -140 T2 + 13300

430 T2 = 20550

T2 = 47.79 °C

The final temperature is 47.79 °C

4 0
3 years ago
Data has been collected to show that at a given wavelength in a 1 cm pathlength cell, Beer's Law for the absorbance of Co2 is li
White raven [17]

Answer : The concentration of a solution with an absorbance of 0.420 is, 0.162 M

Explanation :

Using Beer-Lambert's law :

A=\epsilon \times C\times l

As per question, at constant path-length there is a direct relation between absorbance and concentration.

\frac{A_1}{A_2}=\frac{C_1}{C_2}

where,

A = absorbance of solution

C = concentration of solution

l = path length

A_1 = initial absorbance = 0.350

A_2 = final absorbance = 0.420

C_1 = initial concentration = 0.135 M

C_2 = final concentration = ?

Now put all the given value in the above relation, we get:

\frac{0.350}{0.420}=\frac{0.135}{C_2}

C_2=0.162M

Thus, the concentration of a solution with an absorbance of 0.420 is, 0.162 M

4 0
3 years ago
Which of the following statements are true regarding the effect of flame temperature on atomic absorbance and atomic emission sp
creativ13 [48]

Answer:

the correct option is option c, I and IV

Explanation:

Atomic emission spectroscopy is used to determine quantity of element in a sample.

Atomic emission spectroscopy based on occurring of atomic emission when a valence electron from higher energy orbital comes back to lower energy orbital.

Light intensity emitted by a flame, plasma, arc of particular wavelength are used to excite the valence electron.

The intensity of atomic emission lines are proportional to number of atoms present in the excited state.

Emission intensity is affected by temperature of the excitation source and the efficiency of atomization.

Increase in temperature does not affect the ground state population.

Therefore, statements I and IV are correct.

So, the correct option is c.

7 0
3 years ago
) An organic chemistry lab book gives the following solubility data for oxalic acid 9.5g/100ml water 23.7g/100ml ethanol 16.9g/1
mart [117]

Answer:

Ethanol

Explanation:

Solvent extraction is the process in which a compound transfers from one solvent to another owing to the difference in solubility or distribution coefficient between these two solvents(Science Direct).

We have to remember that oxalic acid will be extracted better into a solvent in which it is more soluble. From the data given; oxalic acid is more soluble in ethanol than in ether.

This simply means that ethanol is a better solvent for extracting oxalic acid  from water when compared to ether.

5 0
2 years ago
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