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marta [7]
3 years ago
5

The terms Q and K refer to reaction components at non-equilibrium and equilibrium conditions, respectively. For a forward reacti

on to be favored in a living cell, which of the following statements describes the relationship between Q and K?
a. The value of Q must be less than that of K.
b. The value of K must be less than that of Q.
c. No conclusion can be drawn about Q and K for a favorable process.
d. Cells are at equilibrium so none of the above statements is true
Chemistry
1 answer:
daser333 [38]3 years ago
8 0

Answer:

The value of Q must be less than that of K.

Explanation:

The difference of K and Q can be understood with the help of an example as follows

         A ⇄ B

In this reaction A is converted into B but after some A is converted , forward reaction stops At this point , let equilibrium concentration of B be [B] and let equilibrium concentration of A be [A]

In this case ratio of  [B] and  [A]  that is

K =  [B] / [A] which is called equilibrium constant.

But if we measure the concentration of A and B ,before equilibrium is reached , then the ratio of the concentration of A and B will be called Q. As reaction continues concentration of A increases and concentration of B decreases. Hence Q tends to be equal to K.

Q = [B] / [A] . It is clear that Q < K before equilibrium.

If Q < K , reaction will proceed towards equilibrium or forward reaction will

proceed .

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The question is incomplete, here is the complete question:

A chemist titrates 110.0 mL of a 0.2412 M hypochlorous acid (HCIO) solution with 0.0613 M NaOH solution at 25°C. Calculate the pH at equivalence. The pKa of hypochlorous acid is 7.50. Round your answer to 2 decimal places

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n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

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Volume of solution = 110.0 mL

Putting values in equation 1, we get:

0.2412M=\frac{\text{Moles of HClO}\times 1000}{110}\\\\\text{Moles of HClO}=\frac{(0.2412\times 110)}{1000}=0.026532mol

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Moles of NaClO = 0.026532 moles

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Putting values in above equation, we get:

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Putting values in above equation, we get:

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