1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
faust18 [17]
3 years ago
9

3954*54534-64563/5435

Mathematics
1 answer:
beks73 [17]3 years ago
7 0

Hey There!

3954 \times 54534 - (64563  \div 5435) \\  = 215627436 - 11.88 \\  = 215627424.120

Hope it helps

You might be interested in
<img src="https://tex.z-dn.net/?f=6%5Csqrt%7B3%7D%2B2%281-%5Csqrt%7B27%7D%29%3D2" id="TexFormula1" title="6\sqrt{3}+2(1-\sqrt{27
skelet666 [1.2K]

Answer:

This is true.

Step-by-step explanation:

Step 1: see that √27 is the same as √3*3*3 and thus 3√3

Step 2: remove parenthesis so that 2(1-3√3) becomes 2 - 6√3

Step 3: observe that the equation now becomes 6√3 + 2 - 6√3 = 2

if you simplify any further, you are left with 0=0, which is true.

Comment if there is any step that requires more details...

3 0
3 years ago
Read 2 more answers
the temperature at noon was -27 degrees . the temperature increased by 13 degrees by 2pm . what was the temperature at 2pm
Aleks [24]
First, you would create an equation for this problem. 
-27 + 13

Now, all you would have to do is solve it. 
-27 + 13 = -14

By 2 pm the temperature was -14 degrees. 

I hope this helps!
5 0
3 years ago
Read 2 more answers
Please please help me im just gonna spam the questions that i dont know until people start answering
natima [27]

Answer:A

Step-by-step explanation:

When graphed it is the only one to semi-complete the pattern

5 0
3 years ago
Lim x approaches 0 (1+2x)3/sinx
jok3333 [9.3K]

Interpreting your expression as

\dfrac{3(1+2x)}{\sin(x)}

when x approaches zero, the numerator approaches 3:

3(1+2x) \to 3(1+2\cdot 0) = 3(1+0) = 3\cdot 1 = 3

The denominator approaches 0, because \sin(0)=0

Moreover, we have

\displaystyle \lim_{x\to 0^-} \sin(x) = 0^-,\quad \displaystyle \lim_{x\to 0^+} \sin(x) = 0^+

So, the limit does not exist, because left and right limits are different:

\displaystyle \lim_{x\to 0^-} \dfrac{3(1+2x)}{\sin(x)}= \dfrac{3}{0^-} = -\infty,\quad \displaystyle \lim_{x\to 0^+}\dfrac{3(1+2x)}{\sin(x)}= \dfrac{3}{0^+} = +\infty

8 0
3 years ago
Please help 15 points<br> x2≥−4
Nutka1998 [239]

Answer:

Solve for  

x

by simplifying both sides of the inequality, then isolating the variable.

Step-by-step explanation:

6 0
4 years ago
Other questions:
  • Which of the following expressions represents the distance between 3/4 and 2?
    8·2 answers
  • F - 3/4 = 1/2 what is f?
    7·2 answers
  • Can anyone help me with these 3 problems?
    10·2 answers
  • Joe is a repair technician for a computer company. Each week he has a batch of computers that needs fixed. The number of compute
    6·1 answer
  • Xy^2/xy + x^2y^2<br> ANSWER ASAP WILL GIVE BRAINLY
    15·1 answer
  • If the radius of a circle is 111, what is the diameter?
    7·2 answers
  • 2x + 22 = 4(x + 3)<br> Please help me
    8·2 answers
  • Antonio pays y dollars per visit to his fitness center and he pays his bills every 3 months . In October he visited the gym 22 t
    14·1 answer
  • Answers for the 3 boxes please ​
    6·2 answers
  • At the library, 56 people borrowed
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!