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Hoochie [10]
3 years ago
13

6. Which process was used to obtain the equation shown in Step 2?

Mathematics
1 answer:
frozen [14]3 years ago
3 0

Answer:

A) added to both sides of the equation

Step-by-step explanation:

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Is 33.3 greater than 33.081
sweet-ann [11.9K]
Yes, because in the tenths place (the number right after the decimal) the number three is greater than the number zero.
7 0
4 years ago
Solve the system if possible by using Cramer's rule. If Cramer's rule does not apply, solve the system by using another method.
maks197457 [2]

Answer:

D = 0 , Dx = 4 , Dy = -6 , Dz = 2

Step-by-step explanation:

As per<u> cramer's rule</u>,

D = |   7    6    4  |  = 0

      |   3    3    3  |

      |   4    4    4  |

Dx =  |  10    6    4  | = 4

        |   1    3    3    |

        |   2    4    4   |

Dy = |   7    10    4  | = -6

       |   3    1     3   |

       |   4    2    4   |

Dz =  |  7    6    10 | = 2

        |   3    3    1   |

        |   4    4    2  |

   

7 0
4 years ago
What is the range of y=-3sine(x)-4​
Arturiano [62]

Answer:

[-7,-1]

{y | -7 ≤ y ≤ -1}

Step-by-step explanation:

8 0
4 years ago
The graph showsf(x)and its transformationg(x).
maxonik [38]

The Answer is g(x)=2^x−3 because in the above exponential function graph could be get by this function

3 0
3 years ago
Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Enter a
12345 [234]

Using the normal distribution, the indicated probability is given as follows:

P(7 ≤ x ≤ 11) = 0.6247.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 8, \sigma = 2

P(7 ≤ x ≤ 11) is the <u>p-value of Z when X = 11 subtracted by the p-value of Z when X = 7</u>, hence:

X = 11:

Z = \frac{X - \mu}{\sigma}

Z = (11 - 8)/2

Z = 1.5

Z = 1.5 has a p-value of 0.9332.

X = 7:

Z = \frac{X - \mu}{\sigma}

Z = (7- 8)/2

Z = -0.5

Z = -0.5 has a p-value of 0.3085.

0.9332 - 0.3085 = 0.6247.

More can be learned about the normal distribution at brainly.com/question/28096232

#SPJ1

5 0
1 year ago
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