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Katen [24]
3 years ago
10

An object with a mass of 20 kg has a net force of 80 N acting on it. What is the acceleration of the object?

Physics
2 answers:
Anastaziya [24]3 years ago
5 0

Answer:

acceleration  =  4 m/s²

Explanation:

alexdok [17]3 years ago
4 0
Newton's 2nd law of motion says

                   Net force = (mass) x (acceleration)

Plug in the things you know, and you have

                   80 N  =  (20 kg) x (acceleration)

Divide each side by (20 kg) :

                  80N / 20kg  =  acceleration

                   acceleration  =  4 m/s²
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When the input voltages of a difference amplifier are 5.1 v and 6.4 v, the output voltage is 64.7 v. The inputs are changed to 4
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Answer:

a) Differential mode gain = 48

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Explanation:

The output of a difference amplifier is related to the input by the equation:

V_{0} = A_{1} V_{1} + A_{2} V_{2} \\

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6.4 A₁ + 5.1 A₂ = 64.7.....................(1)

When V₁ = 5.6 V, V₂ = 4.9 V and V₀ = 35.7 V, the equation becomes

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Multiply equation (1) by 5.6  and (2) by 6.4

35.84 A₁ + 28.56A₂ = 362.32.....................(3)

35.84 A₁ + 31.36 A₂ = 228.48....................................(4)

Subtract equation (3) from (4)

2.8 A₂ = -133.84

A₂ = -133.84/2.8

A₂ = -47.8

Put the value of  A₂ into equation (1)

6.4 A₁ + 5.1 (-47.8) = 64.7

6.4 A₁ = 64.7 + 243.78

A₁ = 308.48/6.4

A₁ = 48.2

a) Common mode gain = A₁ + A₂ = 48.2 + (-47.8)

Common mode gain = 0.4

b) Differential mode gain = (A₁ -A₂)/2

Differential mode gain = (48.2 - (-47.8))/2

Differential mode gain = 96/2

Differential mode gain = 48

c) Common Mode Rejection Ratio (CMRR)

CMRR = |\frac{Differential Mode Gain}{Common Mode Gain} |

CMRR = |\frac{48}{0.4} |\\CMRR = 120

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