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mart [117]
3 years ago
15

As an object increases or decreases, what happens to the total energy?

Physics
1 answer:
kompoz [17]3 years ago
7 0

Answer:As an object speeds up, the total energy increases / decreases / remains the same. As an object slows down, the total energy increases / decreases / remains the same.

Explanation:

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Which three statements about electric magnetic radiation are true
Arada [10]
Do not see the statements

4 0
3 years ago
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Write the meaning of an object has 2 meter length
Ivahew [28]

Answer:

The object has 2 meter length. This means the length is any quantity with a dimension distance. The definition of the length is how long something is or amount of space. In the given data it is stated that, the object is something that has a length of 2 meter.  

<em>Let's take examples to understand. </em>

For example a thread or a table is an object which has a total length of 2 meters.  

Another example is something we are measuring it gives us a result of 2 meters of length by using a meter scale or meter tape.    

Length is a measure of distance and it is a fundamental quantity. Meter is a international system of units (SI units).    



 



4 0
4 years ago
You push a desk with 230 N, but the desk doesn't move due to its friction with the ground. What is the magnitude of the friction
ASHA 777 [7]

Answer:

force \:  = friction \: based \: on \: newtons \: third \: law \\ \: f =  |230|  = 230 \: newton \\ this \: is \: why \: the \: desk \:  \\ doesnt \: move...

3 0
3 years ago
Iron atoms have been detected in the sun's atmosphere, some with many of their electrons stripped away. What is the net electric
BaLLatris [955]

Answer:

2.88 × 10⁻¹⁸ C

Explanation:

The charge on a proton and electron are the same and it is = 1.6 × 10⁻¹⁹ C

The net charge electric charge of an iron atom = (number of proton × charge on a proton) + ( number of electron × charge on an electron ) = 26 (e) + 8 (-e) = 26 e - 8 e = 18 e = 18 ×  1.6 × 10⁻¹⁹ C = 2.88 × 10⁻¹⁸ C

8 0
3 years ago
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A bar of length L = 8 ft and midpoint D is falling so that, when θ = 27°, ∣∣v→D∣∣=18.5 ft/s , and the vertical acceleration of p
777dan777 [17]

Answer:

alpha=53.56rad/s

a=5784rad/s^2

Explanation:

First of all, we have to compute the time in which point D has a velocity of v=23ft/s (v0=0ft/s)

v=v_0+at\\\\t=\frac{v}{a}=\frac{(23\frac{ft}{s})}{32.17\frac{ft}{s^2}}=0.71s

Now, we can calculate the angular acceleration  (w0=0rad/s)

\theta=\omega_0t +\frac{1}{2}\alpha t^2\\\alpha=\frac{2\theta}{t^2}

\alpha=\frac{27}{(0.71s)^2}=53.56\frac{rad}{s^2}

with this value we can compute the angular velocity

\omega=\omega_0+\alpha t\\\omega = (53.56\frac{rad}{s^2})(0.71s)=38.02\frac{rad}{s}

and the tangential velocity of point B, and then the acceleration of point B:

v_t=\omega r=(38.02\frac{rad}{s})(4)=152.11\frac{ft}{s}\\a_t=\frac{v_t^2}{r}=\frac{(152.11\frac{ft}{s})^2}{4ft}=5784\frac{rad}{s^2}

hope this helps!!

6 0
3 years ago
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