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AlladinOne [14]
3 years ago
11

The steps for adding mixed numbers with unlike denominators are very ______

Mathematics
2 answers:
Oliga [24]3 years ago
8 0
It will be different from
12345 [234]3 years ago
7 0

Answer:

the answer is "different from"

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Can someone please help me with this math question? It should be attached. <br> Thanks!
Ad libitum [116K]
If you multiple the net by 2, you will get 2720, and dividing it from 940, you will get 35%. B is the correct answer. :)
8 0
3 years ago
The temperature dropped 5 degrees every hour during 8 hours. How much the temperature drop in all?
Murrr4er [49]

Answer:

<h3>40 degrees</h3>

Step-by-step explanation:

If the temperature dropped 5 degrees every hour, this can be expressed as;

5 degree = 1 hour

To get the total number of degree dropped fro 8hours, we will say;

x degree = 8hours where x is the temperature drop in all

Solving both equality

5 degree = 1 hour

x degree = 8 hours

cross multiply

x * 1 = 5 * 8

x = 40 degrees

<em>Hence the total temperature drop in all is 40°</em>

7 0
4 years ago
In the figure, c // d. What are the measures of &lt;1 and &lt;2? Enter your answers in the boxes. Just write the numbers. (not t
SpyIntel [72]

Answer:  <1 = 105° and <2 = 75°

Step-by-step explanation:

The information we have is the 75 degree angle already provided. Using our knowledge on transverses we know a 180 degree angle is a straight line (we happen to have two of these (c and d)). Using the corresponding angle theorem we know angle 2 is equivalent to 75 degrees. Supplementary angles refer to angles that add up to 180 degrees. Angle 1 and 2 are supplementary so from there we solve.

180 - 75 = 105

<1 = 105 degrees

8 0
3 years ago
Evaluate 8+(-25)+16-(-25)-16
o-na [289]

Answer:

The answer is 8 hope this helps

6 0
3 years ago
Read 2 more answers
Suppose that 5 J of work is needed to stretch a spring from its natural length of 30 cm to a length of 39 cm.
vesna_86 [32]

Answer

given,

work = 5 J

spring stretch form 30 cm to 39 cm

W = \dfrac{1}{2}kx^2

x = 0.39 - 0.30 = 0.09 m

5 = \dfrac{1}{2}k\times 0.09^2

k = \dfrac{5\times 2}{0.09^2}

k = 1234.568 N/m

a) work when spring is stretched from  32 cm to 34 cm

x₂= 0.34 -0.30 = 0.04 m

x₁ = 0.32 - 0.30 = 0.02

W = \dfrac{1}{2}k(x_2^2-x_1^2)^2

W = \dfrac{1}{2}\times 1234.568 \times (0.04^2-0.02^2)^2

W = 0.741 J

b) F = k x

  25 = 1234.568 × x

     x = 0.0205 m

     x = 2.05 cm

3 0
4 years ago
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