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il63 [147K]
3 years ago
11

PLZ HELP ASAP ITS DUE IN AN HOUR, I WILL GIVE BRAINLIST

Chemistry
1 answer:
katen-ka-za [31]3 years ago
4 0

Answer:

d.

Explanation:

hope i help you

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A vessel of volume 22.4 dm3 contains 2.0 mol h2 and 1.0 mol n2 at 273.15 k initially. all the h2 reacted with sufficient n2 to f
yanalaym [24]
Volume = 22.4 dm3
n = 2 mol of H2
n = 1 mol of N2
Temperature = 273.15
All H2 reacts
reaction
N2 + 3H2 = 2NH3
1:3 ratio
Calculation:
N2 initial - N2 reacted = Final N2
1 - 2*(1/3) = 0.3333 mol of N2 left
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NH3 formed = 2/3*1 = 2/3 = 0.666
Total mol:
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Apply the equation : 
PV = nRT
P = nRT/V = 1*0.0082*(273.15)/(22.4) = 0.0999924 atm
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PNH3 = 2/3*0.0999924 = 0.0666616 atm
Answer is 0.0666616 atm
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