Answer:
A lead apron is a <u>non-critical </u> instrument.
Hope it helps!
Answer:
2.02 g H₂
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
Explanation:
<u>Step 1: Define</u>
22.4 L H₂ at STP
<u>Step 2: Identify Conversions</u>
STP - 22.4 L / mol
Molar Mass of H - 1.01 g/mol
Molar Mass of H₂ - 2(1.01) = 2.02 g/mol
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<u>Step 3: Convert</u>
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= 2.02 g H₂
<h3>Answer:</h3>
When a solute is added to a solution, it remains homogeneous because the solute is soluble in given solvent.
<h3>Explanation:</h3>
Homogeneous mixtures, also called true solutions are those mixtures in which the components proportions are same throughout in any given sample. For example, the mixture of table salt (NaCl) and water. When the solution is unsaturated and further NaCl is added to it, it will dissolve the NaCl because the saturation point is still not reached. Remember, as "<em>Like Dissolves Like</em>" NaCl being polar in nature will interact with water molecules and will dissociate into Na⁺ and Cl⁻ ions surrounded by δ- O and δ+ H atoms of water molecules.
<h3>Conclusion:</h3>
In order to form a Homogeneous mixture the solution must be unsaturated, solvent must have affinity for incoming solute particles and the size of solute should be equal to 1 Â (Angstrom).
I would choose organ system
Answer: There are 0.0637 moles present in 85.0 mL of 0.750 M KOH.
Explanation:
Given: Volume = 85.0 mL (1 mL = 0.001 L) = 0.085 L
Molarity = 0.750 M
It is known that molarity is the number of moles of solute present in liter of a solution.
Therefore, moles present in given solution are calculated as follows.

Thus, we can conclude that there are 0.0637 moles present in 85.0 mL of 0.750 M KOH.