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soldier1979 [14.2K]
3 years ago
5

What is the value of P in the equation 3p + 1 =28

Mathematics
2 answers:
DENIUS [597]3 years ago
4 0

Answer:

3p + 1 = 28 \\ 3p = 28 - 1 \\ 3p = 27 \\ p =  \frac{27}{3}  \\ p = 9

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

Olin [163]3 years ago
3 0
First step, we subtract 1 from both sides.
3p+1-1=28-1
3p=27
The second step, is we divide both sides by 3.
3p/3 = 27/3
p=9.
-Isabella
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\bf \textit{hyperbolas, vertical traverse axis }
\\\\
\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h,  k\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2 + b ^2}
\end{cases}\\\\
-------------------------------

\bf \begin{cases}
h=-5\\
k=5\\
a=7\\
c=25
\end{cases}\implies \cfrac{(y-5)^2}{7^2}-\cfrac{[x-(-5)]^2}{b}=1
\\\\\\
\cfrac{(y-5)^2}{7^2}-\cfrac{(x+5)^2}{b}=1\\\\
-------------------------------\\\\
c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b\implies \sqrt{25^2-7^2}=b
\\\\\\
\sqrt{625-49}=b\implies \sqrt{576}=b\implies 24=b\\\\
-------------------------------\\\\
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