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tankabanditka [31]
3 years ago
6

How would you describe the difference between momentum and angular momentum?

Physics
1 answer:
zheka24 [161]3 years ago
3 0

Answer:

Analogous

Explanation:

Momentum is linear

Angular momentum is spinning

momentum is based on the mass and has no geometric component.

Angular momentum is based on moment of inertia and greatly depends on how far the mass is from the center of spin.

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Gauss’s law applies to:_____________
stich3 [128]

Answer:

D. Closed Surfaces

The gaussian surface could be a sphere and can be applied to flat surfaces, but it's always a closed surface.

7 0
4 years ago
Which temperature is the hottest? 98 F or 39 C or 303K?<br> F= 1.8C + 32<br> C= (F-32)/1.8
sergejj [24]

Answer:

The hottest temperature is  T_2 = 39^o C

Explanation:

From the question we are given

    T_1 =  98 F

  T_2 =  39^oC

  T_3 =  303 \  K

Generally converting T_3 to  Fahrenheit

    T_3' =  (T_3 -273 ) * \frac{9}{5}  + 32

=> T_3' =  (303 -273 ) * \frac{9}{5}  + 32

=> T_3' = 86 F

Converting  T_2 to  Fahrenheit

      T_2' =  T_2 * \frac{9}{5}  + 32

=> T_2' =  39 * \frac{9}{5}  + 32

=> T_2' =102.2 F  

Now comparing  the temperature  in Fahrenheit we see that T_2  is the hottest

3 0
3 years ago
If i have a mass of 58.0 kilograms what is my weight
liraira [26]
You would be 127.86 lbs. approx. One kilogram is equal to 2.20 pounds, so you just multiply kilos into the conversion rate. If you are trying to convert pounds to kilos, divide your pounds into the conversion rate.

Hope that helped! :)
7 0
3 years ago
Compare the energy consumption of two commonly used items in the household. calculate the energy used by a 1.20 kw toaster oven,
slamgirl [31]
<span>we know energy = power*time(in hour) so energy used by 1.20kw(1200 watt) toast oven used for 6.2 min(6.2/60 hour) = 1200*(6.2/60)=1200*0.103 = 124 watt hour. Energy used by 11 w cfl used for 8.50 hour = (11*8) + (11* (50/60)) = 88+9.166=97.166 watt hour.</span>
5 0
3 years ago
Read 2 more answers
An engine extracts 441.3kJ of heat from the burning of fuel each cycle, but rejects 259.8 kJ of heat (exhaust, friction,etc) dur
Lilit [14]

Answer:

  • The thermal efficiency is 0.4113.

Explanation:

We know that the thermal efficiency is the ratio of work done by the engine over the heat taken

\eta = \frac{W_{made}}{Q_{in}}

Now, how much work the engine do in a cycle?

We know that the work done in a cycle must be equal to the heat taken minus the heat rejected

W{made} = Q_{in} - Q_{rejected}

So, the thermal efficiency will be:

\eta = \frac{Q_{in} - Q_{rejected}}{Q_{in}}

\eta = \frac{Q_{in}}{Q_{in}} - \frac{Q_{rejected}}{Q_{in}}

\eta = 1 - \frac{Q_{rejected}}{Q_{in}}

Putting the values of the problem

\eta = 1 - \frac{259.8 kJ }{441.3kJ}

\eta = 0.4113

7 0
4 years ago
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