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Korvikt [17]
3 years ago
9

Using spdf notation, what is the electron configuration for a neutral atom of beryllium

Chemistry
1 answer:
kkurt [141]3 years ago
4 0

Answer:

Beryllium

Explanation:

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An unknown compound contains only carbon, hydrogen, and oxygen (). Combustion of 7.50 of this compound produced 11.0 of carbon d
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<span>Firstly, we know that M= m/n,  the main formula which shows the relationship between m, n, and M. The nknown compound contains only carbon, hydrogen, and oxygen, so we can get n(C)=m/M,  from M(C)= m(C)/n (C),  besides the stoechiometric equality, we have </span>

n( C)= m(C)/M(C ) = m(CO2)/ M(CO2)=11/44, because m(CO2)=11.0,  M(CO2)=44.01

so n(C )= 0.24moles,




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4. Why do elements in the same family generally have similar properties?
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3 years ago
What is the ph of a 0.45 m solution of aniline (c6h5nh2)? (pkb  9.40)?
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Answer is: pH of aniline is 9.13.<span>
Chemical reaction: C</span>₆H₅NH₂(aq)+ H₂O(l) ⇌ C₆H₅NH₃⁺(aq) + OH⁻(aq).

pKb(C₆H₅NH₂) = 9.40.

Kb(C₆H₅NH₂) = 10∧(-9.4) = 4·10⁻¹⁰.

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c(C₆H₅NH₃⁺) = c(OH⁻) = x.

c(C₆H₅NH₂) = 0.45 M - x.

Kb = c(C₆H₅NH₃⁺) · c(OH⁻) / c(C₆H₅NH₂).

4·10⁻¹⁰ = x² /  (0.45 M - x). 

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pOH = -log(0.0000134 M.) = 4.87.

pH = 14 - 4.87 = 9.13.

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