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grin007 [14]
3 years ago
10

Why does water have a much higher boiling point than methane even though water (H20) and methane (CH4) molecules are approximate

ly the same size?
A. Only metallic bonds exist between methane molecules.
B. Only Van der Waals forces exist between water molecules.
C. Only metallic bonds exist between water molecules.
D. Only Van der Waals forces exist between methane molecules.​
Chemistry
2 answers:
PSYCHO15rus [73]3 years ago
5 0

Answer:

Water has a higher boiling point because the hydrogen bonds that form water molecules are stronger than the Van der Waals interactions among methane molecules, therefor more energy must be provided in order to break the hydrogen bonds and allow the water molecules to escape the liquid state.

Explanation:

labwork [276]3 years ago
5 0

Answer:

DDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDD

is correct

Explanation:

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The answer is D a compound :)
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Energy pyramid worksheet
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Answer:

From top to bottom coyote, crow, squirrel, then acorn

Explanation:

The coyote has the least amount of energy and its the biggest predator so it belongs at the top. The crows eat squirrels and the squirrels eat acorns.

6 0
3 years ago
Which of the following represents the mass of 1 molecule of SH2?
mr_godi [17]
Answer:
            5.645 × 10⁻²³ g

Solution:

Step 1) Calculate Molar Mass of SH₂;

Atomic Mass of Sulfur    =  32 g/mol

Atomic Mass of H₂         =  2 g/mol
                                      --------------------
Molecular Mass of SH₂  =  34 g/mol

Step 2: Calculate mass of one molecule of SH₂ as;

As,

                     Moles  =  # of Molecules / 6.022 × 10²³

Also, Moles  =  Mass / M.Mass So,

                     Mass/M.mass  =  # of Molecules / 6.022 × 10²³

Solving for Mass,

                     Mass  = # of Molecules × M.mass / 6.022 × 10²³

Putting values,

                     Mass  =  (1 Molecule × 34 g.mol⁻¹) ÷ 6.022 × 10²³

                     Mass  =  5.645 × 10⁻²³ g
5 0
3 years ago
Read 2 more answers
Which ONE of the following is an oxidation–reduction reaction? A) PbCO3(s) + 2 HNO3(aq) ––––> Pb(NO3)2(aq) + CO2(g) + H2O(l)
sveta [45]

Answer:

E) C₂H₄(g) + H₂(g) ⇒ C₂H₆(g)

Explanation:

Which ONE of the following is an oxidation–reduction reaction?

A) PbCO₃(s) + 2 HNO₃(aq) ⇒ Pb(NO₃)₂(aq) + CO₂(g) + H₂O(l). NO. All the elements keep the same oxidation numbers.

B) Na₂O(s) + H₂O(l) ⇒ 2 NaOH(aq). NO. All the elements keep the same oxidation numbers.

C) SO₃(g) + H₂O(l) ⇒ H₂SO₄(aq). NO. All the elements keep the same oxidation numbers.

D) CO₂(g) + H₂O(l) ⇒ H₂CO₃(aq). NO. All the elements keep the same oxidation numbers.

E) C₂H₄(g) + H₂(g) ⇒ C₂H₆(g). YES. <u>C is reduced</u> and <u>H is oxidized</u>.

8 0
3 years ago
Convert the following temperature to c 67k b) 1671k
kap26 [50]
  • Convert Kelvin to °c

(a) 67°c

Formula:-

k=°c+273

°c = 273 - k

°c = 273-67= 206 °c

(b) 1671 k

k=°c+273

°c = 273 - k

°c= 273-1671 = -1398°c

8 0
2 years ago
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