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rewona [7]
3 years ago
7

Calculate the amount of potential difference in a capacitor of 0.9 MF , If the amount of charge is 1.4x10^-4 C .(Show all the wo

rk)
Physics
1 answer:
AURORKA [14]3 years ago
3 0

Answer:

Potential difference V=1.6\times 10^{-10}\ V

Explanation:

Capacitance of capacitor, C = 0.9 MF

Charge, Q=1.4\times 10^{-4}\ C

We need to find the amount of potential difference. We know that,

Q=CV

V is potential difference

So,

V=\dfrac{Q}{C}\\\\V=\dfrac{1.4\times 10^{-4}}{0.9\times 10^6}\\\\V=1.6\times 10^{-10}\ V

So, the required potential difference is 1.6\times 10^{-10}\ V.

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Which statement describes what happens to rocky shorelines that absorb
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B. Solid rock breaks apart.

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which of the following statements best justifies the inclusion of test tube v as a control in the experiment? responses it will
prohojiy [21]

The following statement which best justifies the inclusion of test tube v as a control in the experiment is that it will show the color change that occurs in the absence of enzyme activity and is denoted as option C.

<h3>What is an Enzyme?</h3>

This is referred to as a biological catalyst which is involved in the speeding up of the rate of a reaction by lowering the activation energy used to initiate the reaction.

Enzymes are known as proteinous in nature and are denatured by heat and other substances is included in the test tube v as a control in the experiment is that it will show the color change that occurs in the absence of enzyme activity.

This therefore helps to differentiate the enzymatic processes which takes place in a substance or body therefore making option C the correct choice.

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The options are:

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  • it will provide a measurement of amylase activity at a basic pH.
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It will show the color change that occurs in the absence of enzyme activity.

5 0
1 year ago
Which describes the electric field at the center of a ring of uniform negative charge?.
Bingel [31]

Answer:

A negatively charged particle -q is placed at the center of a uniformly charged ring, where the ring has a total positive charge Q as shown in the following figure. The particle, confined to move along the x axis, is moved a small distance x along the axis ( where x << a) and released. Show that the particle oscillates in simple harmonic motion with a frequency given by,

7 0
2 years ago
A ball is thrown straight up from ground level. It passes a 2-m-high window. The bottom of the window is 7.5 m off the ground. T
slamgirl [31]

Answer:

u=14.48m/s

Explanation:

From the question we are told that:

Height of window h=2m

Height of window off the ground h_g=7.5m

Time to fall and drop t=1.3s

 

Generally the Newton's equation motion  is mathematically given by

 s=ut+\frac{1}{2}at^2

Where

h=ut+\frac{1}{2}at^2

2=u1.3-\frac{1}{2}*9.8*1.3^2

2=u1.3-8.281

u=7.91m/s^2  

Generally the Newton's equation motion  is mathematically given by

2as=v^2-u^2

Where

-2gh_g=v^2-u^2

-2*9.8*7.5=(7.91)^2-u^2

-147=62.5681-u^2

u=\sqrt{209.5681}

u=14.48m/s

Therefore the  ball’s initial speed

u=14.48m/s

8 0
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