Question

Calculate the amount of potential difference in a capacitor of 0.9 MF , If the amount of charge is 1.4x10^-4 C .(Show all the work)

Answer 1

Answer:

Potential difference $V=1.6\times 10^{-10}\ V$

Explanation:

Capacitance of capacitor, C = 0.9 MF

Charge, $Q=1.4\times 10^{-4}\ C$

We need to find the amount of potential difference. We know that,

$Q=CV$

V is potential difference

So,

$V=\dfrac{Q}{C}\\\\V=\dfrac{1.4\times 10^{-4}}{0.9\times 10^6}\\\\V=1.6\times 10^{-10}\ V$

So, the required potential difference is $1.6\times 10^{-10}\ V$.