In what order were the following energy sources discovered by humans

The difference between experimental technique and procedure

kaheart [24]

A procedure is all the steps used to do an experiment in order.
the experiment is when you test your hypothesis and is designed to answer your question. 
the procedure is all the steps of the experiment.

4 0

4 years ago

The same net force is applied to two bodies. The first body acquires half of the acceleration of the second body. What is the re

Yanka [14]

The mass of the first body is double the mass of the second body.

This all revolves around Newtons 2nd law of motion that states F=m*a.

If we understand that body one has the same force applied but half of the acceleration than body two, we can easily understand that it has to do something with the objects mass. This is because mass and acceleration in newtons 2nd law are inversely proportional. This means if and objects force stays the same, but it’s mass doubles, then the acceleration must be half its original value. And if the acceleration doubles and the force stays constant than the mass must have halved from its original value. It sounds quite complicated but it’s very simple. Hopefully this helps!!!

4 0

3 years ago

Air is compressed from 14.7 psia and 60°F to a pressure of 150 psia while being cooled at a rate of 10 Btu/lbm by circulating wa

iren2701 [21]

Answer:

A. 6.36 lbm/s

b. $T_2=341\textdegree F$

Explanation:

a. Given the following information;

#Compressor inlet:

Air pressure, $P_1=14.7psia,T_1=60\textdegree F$

#Compressor outlet:

$Air \ Pressure, P_2=150psia\\\\Air \ volume \ flow \ rate, \dot V_1=5000ft^3/min$

#Cooling rate,

$q_{out}=10Btu/lbm, \dot W=700hp$

# From table A-1E

Gas constant of air $R=0.3704\ psia.ft^3/lbm.R$

Specific enthalpy at $P_1=520R-h_1=124.27Btu/lbm$

Using the mass balance:

$\dot m_{in}-\dot m_{out}=\bigtriangleup \dot m_{sys}=0.0\\\\\dot m_{in}=\dot m_{out}\\\\v_1=\frac{RT_1}{P_1}\\\\v_1=\frac{0.3704\times520}{14.7}\\\\\\v_1=13.1026ft^3/lbm\\\\\dot m=\frac{5000/60}{13.1025}\\\\\dot m=6.36\ lbm/s$

Hence, the mass flow rate of the air is 6.36lbm/s

b The specific enthalpy at the exit is defined as the energy balance on the system:

$\dot m_{in}-\dot m_{out}=\bigtriangleup \dot m_{sys}=0.0\\\\\dot m_{in}=\dot m_{out}\\\\\dot W_{in}+ \dot mh_1=\dot Q_{out}+\dot m_2\\\\h_2=\frac{\dot W_{in}-\dot Q_{out}}{\dot m}+h_1\\\\h_2=\frac{700\times 0.7068-10\times 6.36}{6.36}+124.27\\\\h_2=192.06\ Btu/lbm\\\\#at \ h_2=182.06Btu/lbm, T_2=801R=341\textdegree F$

Hence, the temperature at the compressor exit $T_2=341\textdegree F$

5 0

4 years ago

State three precautions taken when using a metre rule

marishachu [46]

Answer:

1. Our eye should be vertically abvove the point, where the measurement is to be taken.

2. For proper measurement, Keep the ruler exactly along the length , for the measurement

Explanation:

good luck

5 0

3 years ago

How are a concave lens and a convex lens alike? How are they different?

Verdich [7]

ANSWER

A convex lens acts a lot like a concave mirror. ... A concave lens acts a lot like a convex mirror. Both diverge parallel rays away from a focal point, have negative focal lengths, and form only virtual, smaller images.

5 0

3 years ago