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morpeh [17]
3 years ago
5

How are a concave lens and a convex lens alike? How are they different?

Physics
1 answer:
Verdich [7]3 years ago
5 0

ANSWER

A convex lens acts a lot like a concave mirror. ... A concave lens acts a lot like a convex mirror. Both diverge parallel rays away from a focal point, have negative focal lengths, and form only virtual, smaller images.

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Which describes increasing the efficiency of energy resource
vova2212 [387]

Making cars that get better gas mileage

5 0
4 years ago
If the force applied to an object is not greater than the starting friction, what will happen to the object?
bonufazy [111]

Answer:

Explanation:

the object will not move as the force exerted is not sufficient enough to overcome its force of friction

3 0
3 years ago
Read 2 more answers
the electric field midway between two equal but opposite point charges is 573 n/c , and the distance between the charges is 16.0
saveliy_v [14]

The electric potential  between the two charges is 91.68 V.

<h3>Electric potential between the two charges</h3>

The electric potential  between the two charges is calculated as follows;

V = Ed

where;

  • V is electric potential
  • E is electric field
  • d is the distance of the charge

Substitute the given parameters and solve for electric potential,

V = 573 N/c x 0.16 m

V = 91.68 V

Thus, the electric potential  between the two charges is 91.68 V.

Learn more about electric potential here: brainly.com/question/26978411

#SPJ4

4 0
1 year ago
What units is time measured in
Artist 52 [7]

Answer:

The base unit for time is the second (the other SI units are: metre for length, kilogram for mass, ampere for electric current, kelvin for temperature, candela for luminous intensity, and mole for the amount of substance). The second can be abbreviated as s or sec.

Explanation:

6 0
3 years ago
A 10-cm-thick aluminum plate (α = 97.1 × 10−6 m2/s) is being heated in liquid with temperature of 475°C. The aluminum plate has
Anuta_ua [19.1K]

Answer:

T_0 = 338.916 Degree\ celcius

Explanation:

Given data:

Thickness of aluminium sheet 10 cm

initial temperature = 25 degree celcius

Assumption

Thermal properties remain constant, transfer of heat by radiation is negligible.

from the information given in the question we have

T_S ≈T_∞ , it implies we have h → ∞

from table 4.2 Biot number → ∞ the value of

\lambda_1 = 1.5708 and A_1= 1.2732

The fourier number is

t = \frac{\alpha t}{l^2} = \frac{97.1\times 10^{-6} \times 15}{0.05^2} = 0.5826

Temperature at center after 15 second of heating

\theta _{0 wall} = \frac{T_0 - T_{\infity}}{T_i -T_{\infity}} = A_i e^{\lambda_1^2 t}

T_0 = T_i -T_{\infity} \times A_i e^{\lambda_1^2 t}

T_0 = (25 - 475) 1.2732 e^{-1.5708^2 \times 0.5826} +  475  = 356 degree celcius

T_0 = 338.916 Degree\ celcius

8 0
3 years ago
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