Part a)
a) The given function is

We let

Interchange x and y.

Solve for y;



Part b) The range of f(x) refers to y-values for which f(x) exists.
The range of f(x) is

This is because the function is within y=-3 and y=3.
c) The range of

is

The domain is -3≤x≤3
This is because the domain and range of a function and its inverse swaps.
Part d) The graph is shown in the attachment.
3/4 (x+8)=9
3/4x+6=9
-6
3/4x=3
X=4
Check
3/4(4+8)=9
3/4 (12)=9
9=9
Answer:
the value is k=
Step-by-step explanation:
Answer: y + 2 = -7/6 ( x - 4 )