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3 years ago

A ______ employs a weight and a wire to detect horizontal movement.

Physics

2 answers:

Finger [1]3 years ago

7 0

A CREEP METER employs a weight and a wire to detect horizontal movement.

Explanation:

A creep meter is an apparatus utilized to measure ground above an existing fault line has gradually shifted in a horizontal orientation. A creep meter operates by utilizing a wire extended across a fault line. As the ground shifts in a horizontal orientation, the creep meter measures the difference.

eimsori [14]3 years ago

6 0

The answer is creep meter

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Example 2 (5 points) Researchers at a university want to know if higher levels of nitrogen in fertilizer will increase the produ

OlgaM077 [116]

The experiment was well designed.

<h3>What is an experiment?</h3>

An experiment is used to determine cause and effect relationships. We know that in this case, the research is aimed at being able to obtain the relationship that exists between the amount of nitrogen in the soil and the production of tomatoes per plant.

As we could see, the experiment includes a control that serves as a baseline for determining the validity of the results. Further more, the sunlight, water and soil were held constant. The experiment was even repeated further south to verify the results.

Based on a careful review of the experiment, the experiment was well designed.

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2 years ago

¿cual es la velocidad de un haz de electrones que marchan sin desviarse cuando pasan a traves de un campo magnetico perpendicula

Elina [12.6K]

Answer:

La velocidad del haz de electrones es 1.78x10⁵ m/s. Este valor se obtuvo asumiendo que el campo magnético dado (3500007) estaba en tesla y que la fuerza venía dada en nN.

Explanation:

Podemos encontrar la velocidad del haz de electrones usando la Ley de Lorentz:

$F = |q|vBsin(\theta)$ (1)

En donde:

F: es la fuerza magnética = 100 nN

q: es el módulo de la carga del electron = 1.6x10⁻¹⁹ C

v: es la velocidad del haz de electrones =?

B: es el campo magnético = 3500007 T

θ: es el ángulo entre el vector velocidad y el campo magnético = 90°

Introduciendo los valores en la ecuación (1) y resolviendo para "v" tenemos:

$v = \frac{F}{qBsin(\theta)} = \frac{100 \cdot 10^{-9} N}{1.6 \cdot 10^{-19} C*3500007 T*sin(90)} = 1.78 \cdot 10^{5} m/s$

Este valor se calculó asumiendo que el campo magnético está dado en tesla (no tiene unidades en el enunciado). De igual manera se asumió que la fuerza indicada viene dada en nN.

Entonces, la velocidad del haz de electrones es 1.78x10⁵ m/s.

Espero que te sea de utilidad!

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3 years ago

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Inga [223]

Answer:

ghjfglghhukfukxhhfjf

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3 years ago

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Yuliya22 [10]

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3 years ago

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