You are an astronaut in space far away from any gravitational field, and you throw a rock as hard as you can. The rock will:
1 answer:
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a. 46 m/s east
The jet here is moving with a uniform accelerated motion, so we can use the following suvat equation to find its velocity:
where
v is the velocity calculated at time t
u is the initial velocity
a is the acceleration
The jet in the problem has, taking east as positive direction:
u = +16 m/s is the initial velocity
is the acceleration
Substituting t = 10 s, we find the final velocity of the jet:
And since the result is positive, the direction is east.
b. 310 m
The displacement of the jet can be found using another suvat equation
where
s is the displacement
u is the initial velocity
a is the acceleration
t is the time
For the jet in this problem,
u = +16 m/s is the initial velocity
is the acceleration
t = 10 s is the time
Substituting into the equation,
Answer:
a)
b)
Explanation:
Given:
- weight of the stone,
- initial velocity of vertical projection,
- air drag acting opposite to the motion of the stone,
The mass of the stone:
Now the acceleration of the stone opposite of the motion:
where:
d = deceleration
<u>In course of going up the net acceleration on the stone will be:</u>
a)
Now using the equation of motion:
where:
final velocity when the stone reaches at the top of the projectile = 0
h = height attained by the stone before starting to fall down
b)
during the course of descend from the top height of the projectile:
initial velocity,
The acceleration will be:
here the gravity still acts downwards but the drag acceleration acts in the direction opposite to the motion of the stone, now the stone is falling down hence the drag acts upwards.
Using equation of motion:
(+ve acceleration because it acts in the direction of motion)