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3 years ago

You are an astronaut in space far away from any gravitational field, and you throw a rock as hard as you can. The rock will:

Physics

1 answer:

Nesterboy [21]3 years ago

7 0

Answer:

the rock will continue at the same speed unless it is affected by another force such as gravity and so if you threw it it will continue to move unless affected by a force

Explanation:

this is because Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.

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A motorcycle traveling at 15 m/s accelerates at a constant rate of 4.0 m/s over a distance of 50 meters. What is the final veloc

ololo11 [35]

From equations of motion,

v^2 = u^2 + 2as ----- v = final velocity, u = initial velocity, a = acceleration, s = distance covered.

Using the vales given;

v^2 = 15^2 + 2*4*50 = 625
v = Sqrt (625) = 25 m/s

5 0

3 years ago

En una barra de 6m que se utiliza como palanca se coloca el fulcro a 2 m de distancia del extremo derecho, como se muestra en la

Anna007 [38]

Answer:

Fp = 45 N

VMR = 2

VMI = 2

Efficiency = 100%

Explanation:

English Translation

In a 6m bar that is used as a lever, the fulcrum is placed 2m away from the right end, as shown in the figure. At that same end it is required to support a load of 90N. Neglecting lever weight, determined Fp, VMI, VMR and system efficiency

Solution

With the diagram not massively needed to solve this question.

Although, the load of 90 N is placed at the right end of the bar, the fulcrum is placed 2 m from that right end and the balancing force or effort is placed at the extreme most left end of the 6 m bar.

Taking moment about the fulcrum,

The sum of clockwise moments must balance the sum of anti-clockwise moments.

(Load) × (Distance of load from the fulcrum) = (Balancing force) × (Distance of balancing force from fulcrum)

Load = L = 90 N

Distance of load from the fulcrum = 2 m

Balancing force or Effort = Fp = ?

Distance of balancing force from fulcrum = 6 - 2 = 4 m

90 × 2 = Fp × 4

Fp = (180/4) = 45 N

The mechanical advantages are them given as

VMR = (Load)/(Effort) = (90/45) = 2

VMI = (Distance of Effort from the fulcrum)/(Distance of Load from fulcrum) = (4/2) = 2

Efficiency is then given as the VMR divided by VMI in percentage terms

Efficiency = 100% × (VMR/VMI)

Efficiency = 100% × (2/2) = 100%

Hope this Helps!!!

4 0

3 years ago

A wire must be replaced in a circuit by a new wire of the same material but nine times longer. If the new wire's resistance is t

Blizzard [7]

Answer:

three times the original diameter

Explanation:

From the wire's resistance formula, we can calculate the relation between the diameter of the wire and its length:

$R=\rho\frac{l}{\pi \frac{d^2}{4}}\\d=\sqrt{\rho \frac{4 l}{\pi R}}\\$

Here, d is the wire's diameter, $\rho$ is the electrical resistivity of the material and R is the resistance of the wire. We have $l'=9l$

$d'=\sqrt{\rho \frac{4 l'}{\pi R}}\\d'=\sqrt{\rho \frac{4 (9l)}{\pi R}}\\d'=3\sqrt{\rho \frac{4 l}{\pi R}}\\d'=3d$

7 0

3 years ago

A 0.0382-kg bullet is fired horizontally into a 3.78-kg wooden block attached to one end of a massless, horizontal spring (k = 8

wel

Answer:

$280.87$ ms⁻¹

Explanation:

Consider the motion of the bullet-block combination after collision

$m$ = mass of the bullet = 0.0382 kg

$M$ = mass of wooden block = 3.78 kg

$V$ = velocity of the bullet-block combination after collision

$k$ = spring constant of the spring = 833 N m⁻¹

$A$ = Amplitude of oscillation = 0.190 m

Using conservation of energy

Kinetic energy of bullet-block combination after collision = Spring potential energy gained due to compression of spring

$(0.5)(m + M)V^{2} = (0.5)kA^{2}$

$(0.0382 + 3.78)V^{2} = (833)(0.190)^{2}$

$V = 2.81$ ms⁻¹

$v_{o}$ = initial velocity of the bullet before striking the block

Using conservation of momentum for the collision between bullet and block

$m v_{o} = (m + M) V$

$(0.0382) v_{o} = (0.0382 + 3.78) (2.81)$

$v_{o} = 280.87$ ms⁻¹

7 0

3 years ago

The speed of a car increases uniformly from 6 m/s to 42 m/s in 9 second calculate the acceleration of the car

djyliett [7]

The acceleration of the car which changes the speed uniformly is 4 m/s²

<h3>What is acceleration?</h3>

Acceleration can be defined as the rate change of velocity with time.

acceleration a = (Δv) / (Δt)

Given is the initial velocity 6m/s and final velocity 42m/s, the time take fir this change in speed is 9s.

Substitute the values, we have

a = (42-6)/9

a = 36/9

a =4 m/s²

Thus, the acceleration is 4 m/s²

Learn more about acceleration.

brainly.com/question/12550364

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5 0

2 years ago