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Alexxandr [17]
3 years ago
7

The more you stretch a rubber band, the more you can feel it pulling back on your fingers. Which of Newton's laws BEST explains

WHY? A. first B. second C. third
Physics
2 answers:
Naily [24]3 years ago
7 0

Answer:

Explanation:

C3

Genrish500 [490]3 years ago
3 0

Answer: This is an example best explained by Newton's Third Law. This law is based on the observation that all forces in nature and within an isolated system occur in symmetry, that is, for every force exerted on an object there is a force equal in magnitude and with opposite direction (counter-acting force).  This has a consequence that the net force of an isolated system is always zero - in other words a system cannot set itself into motion by generating a net force acting on itself.

The rubber band pulling back is due to the force counteracting your force you exert on the rubber band. The magnitude will be proportional to that of your action.

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A 57 kg person in a rollercoaster moving through the bottom of a curved track of radius 42.7 m feels a normal force of 995 N. Ho
natita [175]

Answer:

Use Fc centripetal force as positive and W the weight as negative

N = m v^2 / R + m g

v^2 = (N - m g) R / m

v^2 = (995 - 57 * 9.8) 42.7 / 57 = 327 m^2/s^2

v = 18.1 m/s

Note: N - m g is the net force producing the centripetal force

5 0
2 years ago
A machine, modeled as a simple spring-mass system, oscillates in simple harmonic motion. Its acceleration is measured to have an
ANTONII [103]

a=5000\dfrac{mm}{s}=5\dfrac{m}{s}

f=10{Hz}\Longrightarrow t=\dfrac{1}{10}s

a_{max}=\dfrac{50\frac{m}{s}}{\frac{s}{10}}\cdot\dfrac{1}{\sqrt{2}}=\dfrac{50\dfrac{m}{s^2}}{\sqrt{2}}\approx\boxed{35.4\dfrac{m}{s^2}}

Hope this helps.

r3t40

5 0
3 years ago
The spring of a toy car is wound by pushing the car
Zepler [3.9K]

The elastic potential energy stored in the car's spring during the process is 3.75 J

<h3>Determination of the spring constant</h3>

From the question given above, the following data were obtained:

  • Force (F) = 15 N
  • Extention (e) = 0.5 m
  • Spring constant (K) =?

K = F/e

K = 15 / 0.5

K = 30 N/m

<h3>Determination of the potential energy</h3>
  • Spring constant (K) = 30 N/m
  • Extention (e) = 0.5 m
  • Potential energy (PE) =?

PE = ½Ke²

PE = ½ × 30 × 0.5²

PE = 15 × 0.25

PE = 3.75 J

Therefore, the elastic potential energy stored in the car's spring during the process is 3.75 J

Learn more about energy stored in spring:

brainly.com/question/4280346

7 0
2 years ago
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How could you record the number 4000 and report 2 significant figures?
yawa3891 [41]

Explanation:

Write in scientific notation.

4000 = 4.0×10³

5 0
3 years ago
How are physical descriptions and physical properties similar
elena55 [62]

They are both used to observe and describe matter.

5 0
3 years ago
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