<span>2 characteristics of stars are shown in an H-R diagram is S</span>ize and Color.
Answer:
The new period of rotation using the new spring would be less than the period of rotation using the original spring
Explanation:
Generally the period of rotation of the mass is mathematically represented as
![T = 2 \pi \sqrt{\frac{I}{k} }](https://tex.z-dn.net/?f=T%20%3D%202%20%5Cpi%20%5Csqrt%7B%5Cfrac%7BI%7D%7Bk%7D%20%7D)
Here I is the moment of inertia of the mass about the rotation axis and k is the spring constant
Now looking at the equation we can tell that T is inversely proportional to the square root of the spring constant which means that for a larger spring constant the time period would be lesser
Answer:
35.7 m
Explanation:
Let
![\mid A\mid=18.5 m](https://tex.z-dn.net/?f=%5Cmid%20A%5Cmid%3D18.5%20m)
![\mid B\mid=41 m](https://tex.z-dn.net/?f=%5Cmid%20B%5Cmid%3D41%20m)
We have to find the distance between Joe's and Karl'e tent.
![A_x=Acos\theta](https://tex.z-dn.net/?f=A_x%3DAcos%5Ctheta)
![A_y=Asin\theta](https://tex.z-dn.net/?f=A_y%3DAsin%5Ctheta)
Substitute the values then we get
![A_x=18.5cos23^{\circ}=17 m](https://tex.z-dn.net/?f=A_x%3D18.5cos23%5E%7B%5Ccirc%7D%3D17%20m)
![A_y=18.5sin 23^{\circ}=7.2 m](https://tex.z-dn.net/?f=A_y%3D18.5sin%2023%5E%7B%5Ccirc%7D%3D7.2%20m)
![B_x=41cos37.5^{\circ}=32.5 m](https://tex.z-dn.net/?f=B_x%3D41cos37.5%5E%7B%5Ccirc%7D%3D32.5%20m)
![B_y=41sin37.5^{\circ}=-24.96 m](https://tex.z-dn.net/?f=B_y%3D41sin37.5%5E%7B%5Ccirc%7D%3D-24.96%20m)
Because vertical component of B lie in IV quadrant and y-inIV quadrant is negative.
By triangle addition of vector
![B=A+C](https://tex.z-dn.net/?f=B%3DA%2BC)
![C=B-A](https://tex.z-dn.net/?f=C%3DB-A)
![C_x=B_x-A_x=32.5-17=15.5 m](https://tex.z-dn.net/?f=C_x%3DB_x-A_x%3D32.5-17%3D15.5%20m)
![C_y=B_y-A_y=-24.96-7.2=-32.16\approx=-32.2 m](https://tex.z-dn.net/?f=C_y%3DB_y-A_y%3D-24.96-7.2%3D-32.16%5Capprox%3D-32.2%20m)
![\mid C\mid=\sqrt{C^2_x+C^2_y}](https://tex.z-dn.net/?f=%5Cmid%20C%5Cmid%3D%5Csqrt%7BC%5E2_x%2BC%5E2_y%7D)
![\mid C\mid=\sqrt{(15.5)^2+(-32.2)^2}=35.7 m](https://tex.z-dn.net/?f=%5Cmid%20C%5Cmid%3D%5Csqrt%7B%2815.5%29%5E2%2B%28-32.2%29%5E2%7D%3D35.7%20m)
Hence, the distance between Joe's and Karl's tent=35.7 m
It is wasted, most likely as light, in this case, or it is lost during the transport of electricity.