Answer:
a) attached below
b) 0.0337
c) 2730.206 Ib
d) 2320.338 ft/min
Explanation:
<u>a) Plot of the drag polar for this aircraft </u>
first we will calculate :
Wing area (s) = Wing span (b) * Average chord length(c)
= 53.3 * 6 = 319.8 ft^2
Aspect ratio = b^2 / s = 8.883
K = 1 /
eAR = 1 /
Drag polar ( Cd ) = 0.02 + 0.044 C^2L
attached below is a plot of the drag polar
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Attached below is the detailed solution of the remaining part of the question
Answer:
umax = 0.1259ft/s
Explanation:
Given:
•Distance between plates, B = 0.01ft
•Pressure difference decrease, 
•Fluid viscosity, u = 10^-³lbf-s/ft²
Specific gravity, S = 0.80
Max velocity in the z-direction will be:
![u_max= [\frac{B^2y}{8u}]\frac{dh}{ds}](https://tex.z-dn.net/?f=u_max%3D%20%5B%5Cfrac%7BB%5E2y%7D%7B8u%7D%5D%5Cfrac%7Bdh%7D%7Bds%7D)

Substituting for h in the first equation, we have:
![\frac{d}{dz}[\frac{p}{y}+z]](https://tex.z-dn.net/?f=%20%5Cfrac%7Bd%7D%7Bdz%7D%5B%5Cfrac%7Bp%7D%7By%7D%2Bz%5D)


= -0.20192
Substituting dh/dz value in the first equation (umax), we have:

umax = 0.1259ft/s
Answer:
Heat flux is 20 W/m^2
Explanation:
Heat flux (Q) is computed as
where h is heat transfer coefficient and ΔT is the difference between body's temperature
From the interior air to the inner wall
From the the outer wall to the exterior air
The wall is under steady-state condition because heat flux is constant