2 years ago

After adjusting your seat, your___ should be as closest possible to the back rest.

Engineering

1 answer:

Crank2 years ago

4 0

Answer:

ans would be back as back is the thing that needs rest by getting closest to seat

You might be interested in

I) A sag vertical curve is to be designed to join a 4% grade to a 2% grade. If the design

Burka [1]

Answer:

=4/5 because I'm not going to go back in a year meaning that they are you are

4 0

1 year ago

Nothing. i have nothing to say but that. other than that im good. :))))

ohaa [14]

Answer:

aw good <3

Explanation:

4 0

2 years ago

A ballistic pendulum consists of a 3.60 kg wooden block on the end of a long string. From the pivot point to the center‐of‐mass

Pavel [41]

Answer:

17.799°

Explanation:

When the bullet hits the block at that time the momentum is conserved

So, initial momentum = final momentum

$P_i=P_f$

So $28\times 10^{-3}\times 210=(3.6+0.028)v_f$

$v_f=1.6207\ m/sec$

Now energy is also conserved

So $\frac{1}{2}\times (3.6+0.028)\times 1.6207^2=(3.6+0.028)\times 9.81\times 2.8(1-cos\Theta )$

$cos\Theta =0.8521So\ \Theta =17.799^{\circ}$

3 0

2 years ago

If a signal is transmitted at a power of 250 mWatts (mW) and the noise in the channel is 10 uWatts (uW), if the signal BW is 20M

Bess [88]

Answer:

C = 292 Mbps

Explanation:

Given:

- Signal Transmitted Power P = 250mW

- The noise in channel N = 10 uW

- The signal bandwidth W = 20 MHz

Find:

what is the maximum capacity of the channel?

Solution:

-The capacity of the channel is given by Shannon's Formula:

C = W*log_2 ( 1 + P/N)

- Plug the values in:

C = (20*10^6)*log_2 ( 1 + 250*10^-3/10)

C = (20*10^6)*log_2 (25001)

C = (20*10^6)*14.6096

C = 292 Mbps

3 0

2 years ago

Bore = 3"

Grace [21]

I need help my self lol XD

5 0

3 years ago

Read 2 more answers