A ductile hot-rolled steel bar has a minimum yield strength in tension and compression of Syt = 60 kpsi and Syc = 75 kpsi. Using
the ductile Coulomb-Mohr theory, determine the factor of safety for the states of plane stress.
1 answer:
Answer:
2.135
Explanation:
Lets make use of these variables
Ox 16.5 kpsi, and Oy --14,5 kpsi
To determine the factor of safety for the states of plane stress. We have to first understand the concept of Coulomb-Mohr theory.
Mohr–Coulomb theory is a mathematical model describing the response of brittle materials such as concrete, or rubble piles, to shear stress as well as normal stress.
Please refer to attachment for the step by step solution.
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Answer:
critical stress = 1382.67 MPa
Explanation:
given data
plane strain fracture toughness = 54.8 MP
length of surface creak = 0.5 mm
we take here
parameter Y = 1.0
solution
we apply critical stress formula that is
critical stress =
.............................1
here K is design stress plane strain fracture toughness and a is length of surface creak so put all these value in equation 1
critical stress =
solve it we get
critical stress = 1382.67 MPa
As exposed stress 1030 MPa is less than critical stress 1382 MPa
so that fracture will not be occur here