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Aleksandr-060686 [28]
3 years ago
15

Merchandise without an expiration date like electronics, tools and home goods typically have a longer

Engineering
1 answer:
Aleks [24]3 years ago
5 0

Answer:

Shelf life.

Explanation:

In Business, an inventory is a term used to describe a list of finished goods, goods still in the production line and raw materials that would be used for the manufacturing of more goods in a bid to meet the unending consumer demands.

Simply stated, an inventory can be classified into three (3) main categories; finished goods, work in progress, and raw materials.

An inventory is recorded as a current asset on the balance sheet because it's primarily the most important source of revenue for a business entity.

Also, the three (3) main cost concept associated with an inventory are;

1. First In First Out (FIFO).

2. Last In First Out (LIFO).

3. Weighted average cost.

Shelf life can be defined as a measure of the length of time that a particular product could be kept or stored without it getting bad or becoming unsuitable for use by the consumers. Thus, the shelf life of a product is largely dependent on its expiration date.

Hence, merchandise without an expiration date like electronics, tools and home goods typically have a longer shelf life.

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A non-inductive load takes a current of 15A at 125V. An inductor is then connected in series in order that the same current shal
Norma-Jean [14]

Answer:

The inductance of the inductor is 0.051H

Explanation:

From Ohm's law;

  V = IR .................. 1

The inductor has its internal resistance referred to as the inductive reactance, X_{L}, which is the resistance to the flow of current through the inductor.

From equation 1;

V = IX_{L}

X_{L} = \frac{V}{I} ................ 2

Given that; V = 240V, f = 50Hz, \pi = \frac{22}{7}, I = 15A, so that;

From equation 2,

X_{L}= \frac{240}{15}

    = 16Ω

To determine the inductance of the inductor,

X_{L} = 2\pifL

L = \frac{X_{L} }{2 \pi f}

  = \frac{16}{2*\frac{22}{7}*50 }

 = 0.05091

The inductance of the inductor is 0.051H.

4 0
4 years ago
Khái niệm về môi trường nhiệt nóng và môi trường nhiện lạnh ?
I am Lyosha [343]

Explanation:

उह्ह्नमजज्ल्ह्ह्बनुतनकुहक्जो

7 0
3 years ago
Suppose that a discrete-time signal x(n) is processed by the system with transfer function H (z)=0.01/(z+0.99) before sent to a
PtichkaEL [24]

Answer:

Detailed solution is given below:

8 0
3 years ago
The assembly consists of a brass shell (1) fully bonded to a ceramic core (2). The brass shell [E = 93 GPa, α= 15.1 × 10−6/°C] h
marshall27 [118]

Answer:

ΔT = 62.11°C

Explanation:

Given:

- Brass Shell:

       Inner Diameter d_i = 32 mm

       Outer Diameter d_o = 39 mm

       E_b = 93 GPa

       α_b = 15.1*10^-6 / °C

- Ceramic Core:

       Outer Diameter d_o = 32 mm

       E_c = 310 GPa

       α_c = 3.2*10^-6 / °C

- Unstressed @ T = 8°C

- Total Length of the cylinder L = 160 mm

Find:

Determine the largest temperature increase Δ⁢t that is acceptable for the assembly if the normal stress in the longitudinal direction of the brass shell must not exceed 60 MPa.

Solution:

- Since, α_b > α_c the brass shell is in compression and ceramic core is in tension. The stress in shell is given as б_a:

                              б_b = - 60 MPa

- The force equilibrium can be written as:

                          б_b*A_b + б_c*A_c = 0

Where, б_b is the stress in core

            A_b is the cross sectional area of the shell

            A_c is the cross sectional area of the core

                           б_b*pi*( d_o^2 - d_i^2) / 4  + б_c*pi*( d_i^2) / 4 = 0

                           б_b*( d_o^2 - d_i^2)  + б_c*( d_i^2) = 0

                           б_c = - б_b*( d_o^2 - d_i^2) / ( d_i^2)

Plug in the values:

                           б_c = 60*( 0.039^2 - 0.032^2) / ( 0.032^2)

                           б_c =  29.121 MPa , б_b = - 60 MPa

-  The total strains in both brass shell and ceramic core is given by:

                           ξ_b = α_b*ΔT + б_b / E_b

                           ξ_c = α_c*ΔT + б_c / E_c

- The compatibility relation is:

                           ξ_b = ξ_c

                           α_b*ΔT + б_b / E_b = α_c*ΔT + б_c / E_c

                           ΔT*(α_b - α_c ) = б_c / E_c - б_b / E_b

                           ΔT = [ б_c / E_c - б_b / E_b ] / (α_b - α_c )

Plug in values and solve:

                           ΔT = [ 0.029121 / 310 + 0.06 / 93 ]*10^6 / (15.1 - 3.2 )

                           ΔT = 62.11°C

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