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kipiarov [429]
3 years ago
15

Cost for 1 kg sugar is 42 dollars how much is 380 grams worth​

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
4 0

Answer:

9.047619047619048

Step-by-step explanation:

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What property is shown in the example below?
Pavlova-9 [17]

Answer:

Associative

Step-by-step explanation:

7 0
3 years ago
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together Preston and Horatio have 49 video game Horatio has 11 more games than Preston how many games does each person have
Bingel [31]
Preston has 19 games and Horatio has 30 games.
You can set this as a system of equations, set Preston as x and Horatio as y.
Both of the amounts add up to 49, so we can get the equation:
x+y=49

Since Horatio has 11 more games, we can get the equation:
y-x=11

If we add the x to the other side, the second equation becomes: 
y=x+11

We can plug in the second equation into the first and get the equation:
x+11+x=49

with a little simplification, we get x (Preston) is equal to 19. If we add 11 to it, we get Horatio's amount: 30
7 0
4 years ago
Look at the figure. If ∆LMC ≅ ∆BJK, then _____ ≅ ∆KB<br> A. BJ<br> B. CM<br> C. ML<br> D. CL
Svetlanka [38]
The answer to your question is D.CL
8 0
3 years ago
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5. Find the sum of the first 35 terms of the arithmetic sequence when a = 5 and d = 4
Elza [17]

Answer:

The sum of the first 35 terms of the arithmetic sequence when a = 5 and d = 4 is 2555.

Step-by-step explanation:

Given:

a = 5

d =  4

To Find :

The sum of first 35 terms of the arithmetic sequence  = ?

Solution:

Step 1 : finding the 35th term

a_n = a_1 +(n-1)d

a_35 = 5 +(35-1)4

a_35 = 5 +(34)4

a_35 = 5 +136

a_35 = 141

Step 2: Finding the sum of first 35 terms

S_n = \frac{n(a_1 +a_n)}{2}

Substituting the values

S_n = \frac{35(5+141)}{2}

S_n = \frac{35(146)}{2}

S_n = \frac{35(146)}{2}

S_n = \frac{5110)}{2}

S_n = 2555

7 0
4 years ago
Hannah și Cassie au împreuna 24 ani Ce varst ATE fiecare dacă Hannah este mai mare cu 6 ani decât sora ei?
satela [25.4K]

Answer:

please speak English

Step-by-step explanation:

just speak English

8 0
3 years ago
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