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cupoosta [38]
3 years ago
5

The purpose of warfare in our world

Chemistry
2 answers:
Fudgin [204]3 years ago
8 0

Answer

We are currently working on a dataset of war and large-scale violent events over the long run. If you want to contribute to this research please get in touch.

Explanation:

almond37 [142]3 years ago
5 0
A war is typically fought by a country or group of countries against an opposing country or group with the aim of achieving an objective through the use of force. Wars can also be fought within a country in the form of a civil or revolutionary war.
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How many grams are in 4.65 mol of AI(NO2)3
nirvana33 [79]
To find out how many grams are in 4.65 moles of Al(NO₂)₃
Find out what the molar mass of Al(NO₂)₃ is
Al = 26.98 g/mol Al
N = 14 g/mol N
O = 16 g/mol O
Next, you have to look at the subscripts and figure out which they belong to, in this case:
Al = 26.98 g/mol Al
N₃ = 42 g/mol N₃
O₆ = 96 g/mol O₆
Finally, add the numbers together, so:
26.98 g/mol Al + 42 g/mol N₃ + 96 g/mol O₆ = 
164.98 g/mol Al(NO₂)₃
Now, you have 4.65 mol Al(NO₂)₃ so
164.98 g/mol Al(NO₂)₃ × 4.65 mol Al(NO₂)₃ =
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6 0
3 years ago
Which statement best describes an array of 10 elements where the elements are of a class type?
ladessa [460]
The array will be created with the elements equal to null.
3 0
3 years ago
What data should be plotted to show that experimental concentration data fits a first-order reaction? A) 1/[reactant] vs. time B
natita [175]

Answer:

C) In[reactant] vs. time

Explanation:

For a first order reaction the integrated rate law equation is:

A = A_{0}e^{-kt}

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Taking ln on both sides gives:

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Therefore a plot of ln[A] vs t should give a straight line with a slope = -k

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3 years ago
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pashok25 [27]

Answer:

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In principle, 3.386 kPa is equivalent to the atmospheric pressure of 1 inch of mercury. Thus, 30.51 inches of mercury is equivalent to 30.51 in *(3.386 kPa/1 in) = 103.307 kPa.

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Explanation:

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