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Arada [10]
3 years ago
15

A dead fish has washed up on the beach and is starting to decay. Which compound produces the unpleasant odor from the decaying f

ish?
pentane-1,5-diamine
hexane-1,5-diamine
hexane-1,6-dithiol
2-pentanone
Chemistry
2 answers:
Tems11 [23]3 years ago
8 0
<h2>Answer:</h2>

<u>The correct answer is pentane-1,5-diamine</u>

<h2>Explanation:</h2>

The distinctive smell of dead animals comes largely from molecules like cadaverine and putrescine that are made when proteins break down, but the decomposition of high-protein plants can make a deathly smell too. Cadaverine is a foul-smelling diamine compound produced by the putrefaction of animal tissue. Cadaverine is a toxic diamine with the formula NH2(CH2)5NH2, which is similar to putrescine. It is the chemical that comes from dead fish

finlep [7]3 years ago
5 0
The correct option in here is the first one: <span>pentane-1,5-diamine. This is also known as cadaverine. This is a common compund that produces that unpleasant odor from the fish. </span>
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3.955*10^48

Explanation:

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1.20×10−8s to nanoseconds
AveGali [126]

Answer:

There are 12 nanoseconds in 1.2\times 10^{-8}\ s.

Explanation:

We need to convert 1.2\times 10^{-8}\ s to nanoseconds.

We know that,

1\ s=10^9\ ns

Now using unitary method to solve it such that,

1.2\times 10^{-8}\ s=1.2\times 10^{-8}\ \times 10^9\\\\=1.2\times 10\\\\=12\ ns

So, there are 12 nanoseconds in 1.2\times 10^{-8}\ s.

7 0
3 years ago
Does 1 gram of phosphorus react with 6 grams of iodine to form 4 grams of phosphorus triodine in P4(s)+6I2(s)=4PI3(s)
mafiozo [28]

Answer:

No

Explanation:

One mole of P₄ react with six moles of I₂ and gives 4 moles of PI₃.

When one gram phosphorus and 6 gram of  iodine react they gives 8.234 g ram of PI₃ .

Given data:

Mass of phosphorus = 1 g

Mass of iodine = 6 g

Mass of  PI₃ = ?

Solution:

Chemical equation:

P₄ + 6I₂    →  4PI₃

Number of moles of P₄:

Number of moles = Mass /molar mass

Number of mole = 1 g / 123.9 g/mol

Number of moles  = 0.01 mol

Number of moles of I₂:

Number of moles  = Mass /molar mass

Number of moles = 6 g / 253.8 g/mol

Number of moles = 0.024 mol

Now we will compare the moles of PI₃ with I₂ and P₄.

                I₂              :              PI₃

                  6              :               4

                 0.024       :             4/6×0.024 = 0.02

                  P₄            :               PI₃

                 1                :                4

                 0.01          :               4 × 0.01 = 0.04  mol

The number of moles of PI₃ produced by I₂ are less it will be limiting reactant.

Mass of PI₃ = moles × molar mass

Mass of PI₃ = 0.02 mol × 411.7 g/mol

Mass of PI₃ =  8.234 g

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