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Luden [163]
4 years ago
13

Solve for t In(A/B) -kt where B-1.65 x 102 M A 1.00 x 10 M. k-4.80 x 104s* and t=

Chemistry
1 answer:
myrzilka [38]4 years ago
4 0

Answer:

t=5.84\times 10^{-5}s

Explanation:

  • First rearrange the whole equation by keeping t in one side and rest parameters in another side of equation
  • Then plug-in all the given values for each parameters and get the solution

ln(\frac{A}{B})=-kt

or, t=\frac{1}{-k}\times ln(\frac{A}{B})

Now plug-in all given values:

t=\frac{1}{-4.80\times 10^{4}s^{-1}}\times ln(\frac{1.00\times 10M}{1.65\times 10^{2}M})

So, t=5.84\times 10^{-5}s

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igor_vitrenko [27]

Answer:

Element

magnesium, hydrogen, chlorine, sulfur

Compound

water, iron oxide

Mixture

air, salty water , dias cola.

Explanation:

Element is made up of only one type of atom and are relresented by symbols.

Compound are formed by chemical mixing of atoms of elements and have a chemical formula

Mixture are formed by simple mixing up of substances and mixture don't have chemical formula.

4 0
3 years ago
Be sure to answer all parts. Consider the reaction N2(g) + 3H2(g) → 2NH3(g)ΔH o rxn = −92.6 kJ/mol If 3.0 moles of N2 react with
Alex787 [66]

Answer:

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Explanation:

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6 0
4 years ago
A force of 20 N acts upon 5 kg block caculate the accerleration of the object
Vedmedyk [2.9K]

Answer:

\boxed{\text{4 m $\cdot$ s$^{-2}$}}

Explanation:

F = ma

a = \dfrac{F}{m} = \dfrac{\text{20 N}}{\text{5 kg}} \times \dfrac{\text{1 kg$\cdot$ m $\cdot$ s$^{-2}$}}{\text{1 N}} = \text{4 m $\cdot$ s$^{-2}$}\\\\\text{The acceleration of the object is } \boxed{\textbf{4 m $\cdot$ s$^{\mathbf{-2}}$}}

 

4 0
3 years ago
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Answer:

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Explanation:

6 0
3 years ago
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Damm [24]

Answer:

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Explanation:

During oxidative phosphorylation, the electrons from NADH and FADH₂ are combined with O₂ and the energy released in the process is used to synthesize ATP from ADP.

The components of the electron transport chain are located in the internal part of the mitochondrial membrane in eukaryotic cells, and in the cell membrane in bacteria. The transporters in the electron transport chain are organized into four complexes in the inner mitochondrial membrane. A fifth complex then couples these reactions to the ATP synthesis.

Complex II receives the electrons from the succinate, which is an intermediary in the Krebs cycle. These electrons are transferred to the FADH₂ and then to the Q coenzyme. This liposoluble molecule will transport the electrons from Complex II to Complex III. In this complex, the electrons are transferred from the <em>b</em> cytochrome to the <em>c</em> cytochrome. This <em>c </em>cytochrome, which is a peripheric membrane protein located in the external part of the inner membrane, then transports the electrons to Complex IV where finally they are transferred to the oxygen.

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3 years ago
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