Jeremy is walking through the woods, marking diseased trees for removal. He walks for 2.44 km, at a heading of 13.9° west of nor
1 answer:
We conclude that Jeremy walked 2.37km North and 0.59 km West.
<h3>How to get the North and West components?</h3>
We can assume that the distance that he walked is the hypotenuse of a right triangle, like the one you can see in the image below.
There, you can see that the adjacent cathetus would be the displacement in the North direction, while the opposite cathetus would be the displacement in the West direction.
Then we can use the relations.
- Sin(θ) = (opposite cathetus)/(hypotenuse)
- Cos(θ) = (adacent cathetus)/(hypotenuse).
With θ = 13.9° and hypotenuse = 2.44km
Solving these two we will get:
sin(13.9°) = Y/2.44km
sin(13.9°)*2.44km = Y = 0.59 km
cos(13.9°) = X/2.44km
cos(13.9°)*2.44km = X = 2.37km
So we can conclude that he walked 2.37km North and 0.59 km West.
If you want to learn more about right triangles, you can read:
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Answer:
489.19m
Explanation:
To find the minimum distance you first calculate the time in which the teacher stops:
however, the reaction of the teacher is 0.31s later, then you use
t=13.8-0.31s=13.49s
during this time the camper has traveled a distance of:
(1)
Next you calculate the distance that teacher has traveled for 13.6s:
(2)
The minimum distance between the driver and the camper will be the difference between (2) and (1):
A) 16.1 N
The magnitude of the electric force between the corks is given by Coulomb's law:
where
k is the Coulomb's constant
is the magnitude of the charge on the first cork
is the magnitude of the charge of the second cork
r = 0.12 m is the separation between the two corks
Substituting numbers into the formula, we find
B) Attractive
According to Coulomb's law, the direction of the electric force between two charged objects depends on the sign of the charge of the two objects.
In particular, we have:
- if the two objects have charges with same sign (e.g. positive-positive or negative-negative), the force is repulsive
- if the two objects have charges with opposite sign (e.g. positive-negative), the force is attractive
In this problem, we have
Cork 1 has a positive charge
Cork 2 has a negative charge
So, the force between them is attractive.
C)
The net charge of the negative cork is
We know that the charge of a single electron is
The net charge on the negative cork is due to the presence of N excess electrons, so we can write
and solving for N, we find the number of excess electrons:
D)
The net charge on the positive cork is
We know that the charge of a single electron is
The net charge on the positive cork is due to the "absence" of N excess electrons, so we can write
and solving for N, we find the number of electrons lost by the cork: