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olga nikolaevna [1]
3 years ago
13

Rosalind is an impulsive child who seldom waits for her turn when playing with other children. Rosalind's father is also an impu

lsive individual who often seems to act before he thinks. The theorist who would most likely suggest that Rosalind has learned to be impulsive from watching her father is:_______
A) Sigmunt Freud
B) B.F. Skinner
C) Alburt Bandura
D) Carl Rogers
Physics
1 answer:
wariber [46]3 years ago
3 0

Answer:

Alburt Bandura

Explanation:

Rosalind has learned to be impulsive and seldom waits for her turn when playing with other children, this trait she has learned  from her father, who is also an impulsive man.

The theorist who would most likely suggest that Rosalind has learned to be impulsive from watching her father is Alburt Bandura. Alburt in his famous Bebo Doll experiment confirmed that children learn from the adults behavior in their life.

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POR FAVOR AYUDENME A COMLETARLO
Zigmanuir [339]

Answer:

English please?

Explanation:

8 0
3 years ago
Properties such as luster conductivity and flexibility are used to describe what type of elements
pickupchik [31]
Answer: metals.

Justification:

There are 118  elements which you can find in the periodic table ordered by atomic number. Those elements my be classified into metals, non-metals and metalloids.

The metals are placed on the left side of the periodic table. The metals share the properties of luster, conductivity and flexibility.

The properties of non-metals (which are on the right side of the periodic table) are opposite to those of metals: opaque, low conductivity and brittle.

Metalloids have in between properties.

Copper, for example is a metal: it has luster, is flexible and is highly conductive of the electricity (and temperature).


4 0
3 years ago
Neutron stars are extremely dense objects that are formed from the remnants of supernova explosions. Many rotate very rapidly. S
Alja [10]

Answer:

16294 rad/s

Explanation:

Given that

M(ns) = 2M(s), where

M(s) = 1.99*10^30 kg, so that

M(ns) = 3.98*10^30 kg

Again, R(ns) = 10 km

Using the law of gravitation, the force between the Neutron star and the sun is..

F = G.M(ns).M(s) / R²(ns), where

G = 6.67*10^-11, gravitational constant

Again, centripetal force of the neutron star is given as

F = M(ns).v² / R(ns)

Recall that v = wR(ns), so that

F = M(s).w².R(ns)

For a circular motion, it's been established that the centripetal force is equal to the gravitational force, hence

F = F

G.M(ns).M(s) / R²(ns) = M(s).w².R(ns)

Making W subject of formula, we have

w = √[{G.M(ns).M(s) / R²(ns)} / {M(s).R(ns)}]

w = √[{G.M(ns)} / {R³(ns)}]

w = √[(6.67*10^-11 * 3.98*10^30) / 10000³]

w = √[2.655*10^20 / 1*10^12]

w = √(2.655*10^8)

w = 16294 rad/s

7 0
3 years ago
A 0.5 kg stone is raised from 1m to 2m height from the ground. what is the change in potential energy of the stone?
Usimov [2.4K]

Given: The mass of stone (m) = 0.5 kg

Raised from heights (h₁) = 1.0 m to (h₂) = 2.0 m

Acceleration due to gravity (g) = 9.8 m/s²

To find: The change in potential energy of the stone

Formula: The potential energy (P) = mgh

where, all alphabets are in their usual meanings.

Now, we shall calculate the change in potential energy of the stone

Δ P = P₂ - P₁ = mg (h₂ - h₁)

or,                = 0.5 kg ×9.8 m/s² ×(2.0 m - 1.0 m)

or,                = 4.9 J

Hence, the required change in the potential energy of the stone will be 4.9 J

4 0
3 years ago
You can increase the vapor pressure of a liquid by:
irga5000 [103]

Answer: Option (c) is the correct answer.

Explanation:

Vapor pressure is defined as the pressure exerted by vapors or gas on the surface of a liquid.

When we increase the temperature of a liquid substance then there will occur an increase kinetic energy of the molecules. As a result, they will move readily from one place to another.

Hence, liquid state of a substance will change into vapor state of the substance. This means that an increase in temperature will lead to an increase in vapor pressure of the substance.

Thus, we can conclude that you can increase the vapor pressure of a liquid by increasing temperature.

4 0
3 years ago
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